...i need the answer to that too...
A quadratic function can only have either a maximum or a minimum point, not both. The shape of the graph, which is a parabola, determines this: if the parabola opens upwards (the coefficient of the (x^2) term is positive), it has a minimum point; if it opens downwards (the coefficient is negative), it has a maximum point. Therefore, a quadratic function cannot exhibit both extreme values simultaneously.
The quadratic parent function is given by the equation ( f(x) = x^2 ). This function has a minimum vertex at the point (0, 0), which is the lowest point on the graph. Since the parabola opens upward, there is no maximum vertex. The minimum value occurs when ( x = 0 ), yielding ( f(0) = 0 ).
To determine if a vertex is a minimum in a quadratic function, you can analyze the coefficient of the quadratic term (the leading coefficient). If the coefficient is positive, the parabola opens upwards, indicating that the vertex is a minimum point. Additionally, you can use the second derivative test; if the second derivative at the vertex is positive, the vertex is confirmed as a minimum.
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
Yes
It if the max or minimum value.
The minimum is the vertex which in this case is 0,0 or the origin. There isn't a maximum.....
if it opens up then the point is called the minimum if it opens down its called the maximum
A quadratic function can only have either a maximum or a minimum point, not both. The shape of the graph, which is a parabola, determines this: if the parabola opens upwards (the coefficient of the (x^2) term is positive), it has a minimum point; if it opens downwards (the coefficient is negative), it has a maximum point. Therefore, a quadratic function cannot exhibit both extreme values simultaneously.
In theory you can go down the differentiation route but because it is a quadratic, there is a simpler solution. The general form of a quadratic equation is y = ax2 + bx + c If a > 0 then the quadratic has a minimum If a < 0 then the quadratic has a maximum [and if a = 0 it is not a quadratic!] The maximum or minimum is attained when x = -b/2a and you evaluate y = ax2 + bx + c at this value of x to find the maximum or minimum value of the quadratic.
It can't - unless you analyze the function restricted to a certain interval.
The quadratic parent function is given by the equation ( f(x) = x^2 ). This function has a minimum vertex at the point (0, 0), which is the lowest point on the graph. Since the parabola opens upward, there is no maximum vertex. The minimum value occurs when ( x = 0 ), yielding ( f(0) = 0 ).
vertex
To determine if a vertex is a minimum in a quadratic function, you can analyze the coefficient of the quadratic term (the leading coefficient). If the coefficient is positive, the parabola opens upwards, indicating that the vertex is a minimum point. Additionally, you can use the second derivative test; if the second derivative at the vertex is positive, the vertex is confirmed as a minimum.
Standard notation for a quadratic function: y= ax2 + bx + c which forms a parabola, a is positive , minimum value (parabola opens upwards on an x-y graph) a is negative, maximum value (parabola opens downward) See related link.
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
Yes