The rectangle is 4 feet by 11 feet and its area is 44 square feet.
(Normally the "length" would be given as the longer side.)
Perimeter is the sum of the measures of the sides of a figure. The formula for the perimeter of a rectangle is P = 2L + 2W, with L standing for length and W standing for width. Simply stated, you add up the two longer sides and the two shorter sides. If the perimeter is 30 and the length is 4, you can substitute those values into the formula and solve for the unknown quantity, W, the width. So, 30 = 2(4) + 2W. Then, 2W = 22 and W = 11. Now that you know the width of the rectangle, you can find its area. The formula for the area of a rectangle is A = LW, or area equals the length times the width, measured in square units. So in this example, the area = 4 x 11 or 44 square feet.
P = 2L + 2 W
P = 8 + 2W = 30
2W = 30 - 8 = 22
W = 11
A = W x L = 11 x 4 = 44
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
Area is 1.44 square feet Perimeter is 6 feet.
24 feet square feet
The length should be 6cm and the width is 4cm.
Length: 4; Width: 5 or Length: 5; Width: 4
The perimeter is 18 feet.
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
Area is 1.44 square feet Perimeter is 6 feet.
The perimeter is 30 feet for this rectangle.
98 square feet
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
6 feet... area 24 perimeter 20
24 feet square feet
The length should be 6cm and the width is 4cm.
The perimeter of a rectangle with a length of 8.5 feet and a width of 4.5 feet is 26.
Length: 4; Width: 5 or Length: 5; Width: 4
Area = 8*24 =192 square feet Perimeter = 24+24+8+8 = 64 feet