In a symmetric distribution, the mean and median will always be equal. This is because symmetry implies that the distribution is balanced around a central point, which is where both the mean (the average) and the median (the middle value) will fall. Therefore, in perfectly symmetric distributions like the normal distribution, the mean, median, and mode coincide at the center. In practice, they may be approximately equal in symmetric distributions that are not perfectly symmetrical due to rounding or sampling variability.
Yes. And in any symmetric distribution, they will.
In a symmetric distribution, the mean, median, and mode are all equal or located at the same central point. This characteristic ensures that the distribution is balanced on either side, with half of the data points falling below the central value and half above it. Therefore, in a perfectly symmetric distribution, such as a normal distribution, these three measures of central tendency coincide.
No.It is asymmetric.
When data has the same frequency and the same distribution, it means that the data points are evenly spread across their range, resulting in a uniform pattern. A symmetric distribution indicates that the data is balanced around a central point, such as the mean, with equal amounts of data on either side. Common examples of symmetric distributions include the normal distribution and the uniform distribution. In such cases, the measures of central tendency (mean, median, and mode) will coincide.
If it is a symmetric distribution, the median must be 130.
Yes, they can.Yes, they can. In a symmetric distribution they will be the same.
Mean
No. The mean and median are not necessarily the same. They will be the same if the distribution is symmetric but the converse is not necessarily true. That is to say, a distribution does not have to be symmetric for the mean and median to be the same. For example, the mean and median of {1, 1, 5, 6, 12} are both 5 but the distribution is NOT symmetric.
yes
In a symmetric distribution, the mean and median will always be equal. This is because symmetry implies that the distribution is balanced around a central point, which is where both the mean (the average) and the median (the middle value) will fall. Therefore, in perfectly symmetric distributions like the normal distribution, the mean, median, and mode coincide at the center. In practice, they may be approximately equal in symmetric distributions that are not perfectly symmetrical due to rounding or sampling variability.
That would provide some evidence that the distribution is symmetric about the mean (or median).
That would provide some evidence that the distribution is symmetric about the mean (or median).
Median.
Yes. And in any symmetric distribution, they will.
The t-distribution is symmetric so the question is irrelevant.The t-distribution is symmetric so the question is irrelevant.The t-distribution is symmetric so the question is irrelevant.The t-distribution is symmetric so the question is irrelevant.
It means that the probability density function is symmetric about 0.