In a symmetric distribution, the mean and median will always be equal. This is because symmetry implies that the distribution is balanced around a central point, which is where both the mean (the average) and the median (the middle value) will fall. Therefore, in perfectly symmetric distributions like the normal distribution, the mean, median, and mode coincide at the center. In practice, they may be approximately equal in symmetric distributions that are not perfectly symmetrical due to rounding or sampling variability.
Yes, in a normal distribution, the mean is always equal to the median. This is because the normal distribution is symmetric around its mean, meaning that the values are evenly distributed on both sides. As a result, the central tendency measured by both the mean and the median coincides at the same point.
Yes. And in any symmetric distribution, they will.
The relationship between the mean and the median depends on the shape of the distribution. In a symmetric distribution, the mean and median are equal, so if the mean is 105, the median would also be 105. However, if the distribution is skewed, the median could be less than or greater than the mean. Without additional information about the distribution's shape, we cannot definitively determine the median.
In a symmetric distribution, the mean, median, and mode are all equal or located at the same central point. This characteristic ensures that the distribution is balanced on either side, with half of the data points falling below the central value and half above it. Therefore, in a perfectly symmetric distribution, such as a normal distribution, these three measures of central tendency coincide.
If the wide range is evenly spread between the very small and the very large (the distribution is symmetric) then there is not much to choose between the median and the mean. If not, the median will have some advantages as a measure of central tendency.
If it is a symmetric distribution, the median must be 130.
No. The mean and median are not necessarily the same. They will be the same if the distribution is symmetric but the converse is not necessarily true. That is to say, a distribution does not have to be symmetric for the mean and median to be the same. For example, the mean and median of {1, 1, 5, 6, 12} are both 5 but the distribution is NOT symmetric.
Yes, they can.Yes, they can. In a symmetric distribution they will be the same.
Mean
yes
That would provide some evidence that the distribution is symmetric about the mean (or median).
That would provide some evidence that the distribution is symmetric about the mean (or median).
Yes, in a normal distribution, the mean is always equal to the median. This is because the normal distribution is symmetric around its mean, meaning that the values are evenly distributed on both sides. As a result, the central tendency measured by both the mean and the median coincides at the same point.
Median.
Yes. And in any symmetric distribution, they will.
If the distribution is not symmetric, the mean will be different from the median. A negatively skewed distribution will have a mean hat is smaller than the median, provided it is unimodal.
All equal.