(X+4)2=256
X+4=16
X=8
the sides of the original square is 8 cm
5cm because the square root of 121 is 11 and 5 plus 6 equals 11.
The new square has an area of 121, so the length of a side is the square root of 121, or 11. So the length of the side of the old square was 10.
If the length of a side of a square is doubled, the perimeter also doubles. The perimeter of a square is calculated as ( P = 4 \times \text{side length} ). Therefore, if the original side length is ( s ), the new side length becomes ( 2s ), resulting in a new perimeter of ( P = 4 \times 2s = 8s ), which is twice the original perimeter.
It is the square of the original number. If the original number represents a length, then the square of the original number represents an area of a square with side equal to the original number.
(4 times the square root of 'A') centimeters.
256 divise by 4
5cm because the square root of 121 is 11 and 5 plus 6 equals 11.
12 cm
256 = 162; 16 - 7 = 9 cm
New area = 256 so new side = sqrt 256 = 16 so old side = 12 (so old area = 144)
The new square has an area of 121, so the length of a side is the square root of 121, or 11. So the length of the side of the old square was 10.
If the length of a side of a square is doubled, the perimeter also doubles. The perimeter of a square is calculated as ( P = 4 \times \text{side length} ). Therefore, if the original side length is ( s ), the new side length becomes ( 2s ), resulting in a new perimeter of ( P = 4 \times 2s = 8s ), which is twice the original perimeter.
It is the square of the original number. If the original number represents a length, then the square of the original number represents an area of a square with side equal to the original number.
Let the original length of a side be d cm.Then (d + 5)2 = 144 = 122 : d + 5 = 12 : d = 12 - 5 = 7.The original square had a side length of 7 cm.
That depends what you want to calculate. To calculate the area, for a rectangular lot, just multiply length x width; in the special case of a square lot, this becomes length x length, or length square.
(4 times the square root of 'A') centimeters.
9 feet was the original side lengths