256 divise by 4
12 cm
That depends what you want to calculate. To calculate the area, for a rectangular lot, just multiply length x width; in the special case of a square lot, this becomes length x length, or length square.
The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4
The length and width of a square by definition are of equal length. The area (A) of a square = d2, where d is the length of one side. If the area is known, then the length of the side of a square, d = √A (square root of A).
9² = 81 square units.Area= length*length= 9*9= 81 unit square
(X+4)2=256 X+4=16 X=8 the sides of the original square is 8 cm
5cm because the square root of 121 is 11 and 5 plus 6 equals 11.
12 cm
256 = 162; 16 - 7 = 9 cm
The new square has an area of 121, so the length of a side is the square root of 121, or 11. So the length of the side of the old square was 10.
New area = 256 so new side = sqrt 256 = 16 so old side = 12 (so old area = 144)
It is the square of the original number. If the original number represents a length, then the square of the original number represents an area of a square with side equal to the original number.
That depends what you want to calculate. To calculate the area, for a rectangular lot, just multiply length x width; in the special case of a square lot, this becomes length x length, or length square.
Let the original length of a side be d cm.Then (d + 5)2 = 144 = 122 : d + 5 = 12 : d = 12 - 5 = 7.The original square had a side length of 7 cm.
(4 times the square root of 'A') centimeters.
9 feet was the original side lengths
It becomes a bigger rectangle - possibly a square.