Oranges cost 6 cents each. Apples cost 10 cents each.
Solve the problem by treating it as a simultaneous equation question which works out as: Apples: 0.20 each Oranges: 0.10 each
a and b both have the probability of 3/4
The probability is 0.664
Impossible
Oranges cost 6 cents each. Apples cost 10 cents each.
Solve the problem by treating it as a simultaneous equation question which works out as: Apples: 0.20 each Oranges: 0.10 each
Treat it as a simultaneous equation and it works out as: Oranges = 0.10 each Apples = 0.20 each
This is like asking how many apples equals oranges, because cm are length and ml are volume.
A "score" of anything is twenty of that thing. So a score of oranges equals twenty oranges.
The probability of each coin flip, independently, is 0.5 or 50%. The probability of getting one result (either heads or tails) four times in a row is 0.5 to the fourth power or 0.0625, which equals 6.25%
a and b both have the probability of 3/4
The probability that an event will occur plus the probability that it will not occur equals 1.
It does not matter.
The probability is 0.664
about 8 large apples-- 16 medium
Probability equals favorable outcomes divided by total number of outcomes.