Q: If there are two lines that are perpendicular and one of the two slopes is negative one third then what is the slope of the other line?

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one slope is the negative reciprocal of the other

That the slopes of the lines are the opposite of each other and negative. Ex: y=2/3x+b then the line perpendicular to it is y=-3/2+b

One is the negative reciprocal of the other. That is, the product of the two slopes is -1. UNLESS one of them is zero, in which case the slope of the other is infinite.

one is the negative reciprocal of the other; that is if the slope of one line is 2, the other is -1/2

You have to know the slopes of both lines. -- Take the two slopes. -- The lines are perpendicular if (one slope) = -1/(the other slope), or the product of the slopes equals to -1.

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negative reciprocal slopes ---> the lines are perpendicular equal slopes ---> the lines are parallel

The slopes of two perpendicular lines are negative inverses of each other. In other words, the two slopes when multiplied together equal -1.

one slope is the negative reciprocal of the other

Those lines are perpendicular.Those lines are perpendicular.Those lines are perpendicular.Those lines are perpendicular.

Is it possible for two lines with positive slopes to be perpendicular?

Horizontal lines have a slope of zero, and the slope of vertical lines is undefined. Parallel lines have equal slopes, and perpendicular lines have slopes that are negative reciprocals of each other. So we can say that: Two nonvertical lines are parallel if and only if they have the same slope. Two lines are perpendicular if and only if their slopes are negative reciprocals of each other. That is, if the slopes are m1 and m2, then: m1 = - 1/m2 or (m1)(m2) = -1

They are the negative reciprocal of each other. Fo rexample, if a line has slope = +2, then the line perpendicular to it has slope -1/2

That the slopes of the lines are the opposite of each other and negative. Ex: y=2/3x+b then the line perpendicular to it is y=-3/2+b

One is the negative reciprocal of the other. That is, the product of the two slopes is -1. UNLESS one of them is zero, in which case the slope of the other is infinite.

Slopes of parallel lines have the same slope (they are changing at the same rate).Slopes of perpendicular lines have slopes that are the negative inverse of each other, that is, their product is -1. (The slope of a vertical line is therefore undetermined, not infinity. There is no slope s that times 0 equals -1.)---Let m1 be the slope of line one and m2 be the slope of line two. Then:If the lines are parallel, then their slopes are equal, so m1 - m2 = 0.If the lines are perpendicular, then their slopes are negative inverses of each other, so= m1 - (-1/m1)= m1 + 1/m1= (m12 + 1)/m1

one is the negative reciprocal of the other; that is if the slope of one line is 2, the other is -1/2

You have to know the slopes of both lines. -- Take the two slopes. -- The lines are perpendicular if (one slope) = -1/(the other slope), or the product of the slopes equals to -1.