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P(6) = 5/36 = 0.138888... ≈ 13.9%

When two fair dice are rolled, the sample space (all possible outcomes) has 36

equiprobable events:(1,1), (1,2), (1,3), (1,4), (1,5),(1,6), (2,1), (2,2), (2,3), (2,4),

(2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5),

(4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6).

There are 5 events where the sum of the dots of each die is equal to 6:

(1,5), (2,4), (3,3), (4,2), (5,1).

So in two fair dice are rolled the probability that the total number of spots shown is equal to 6 is, P(6) = 5/36 = 0.138888... ≈ 13.9%

Q: If two fair dice are rolled what is the probability that the total number of spots shown is equal to 6?

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If two twelve side fair dice are rolled, there are 144 possible outcomes. Of those 144 outcomes, there are four (1-4, 2-3, 3-2, and 4-1) that add up to five, So the probability of rolling a sum of five is 4 in 144, or 1 in 36.

6 sides on each dice. Each number on the sides is different, this represents the 1 out of all 6 amounts shown. So this is what you'll do for each dice... 1/6 + 1/6 = 2/6 = 1/3

Yes- the highest probability value is the mode. Let me clarify this answer: For a probability mass function for a discrete variables, the mode is the value with the highest probability as shown on the y axis. For a probability density function for continuous variables, the mode is the value with the highest probability density as shown on the y-axis.

a:b, a/b, a to b

The answer depends on how many dice are rolled, whether or not they are fai, how the numbers thrown are combined. For example, in backgammon, a double allows you to move four times the value shown.The answer depends on how many dice are rolled, whether or not they are fai, how the numbers thrown are combined. For example, in backgammon, a double allows you to move four times the value shown.The answer depends on how many dice are rolled, whether or not they are fai, how the numbers thrown are combined. For example, in backgammon, a double allows you to move four times the value shown.The answer depends on how many dice are rolled, whether or not they are fai, how the numbers thrown are combined. For example, in backgammon, a double allows you to move four times the value shown.

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If two fair dice were rolled, there would be 36 outcomes. (1,1),(1,2),....,(6,6) The maximum sum would be 12. Therefore, the probability that the total number of spots shown is equal to 15 is zero.

6 & 4 And 5 & 5 are the only two possibilities, so 4 chances in 36 or 1 in nine.

If two twelve side fair dice are rolled, there are 144 possible outcomes. Of those 144 outcomes, there are four (1-4, 2-3, 3-2, and 4-1) that add up to five, So the probability of rolling a sum of five is 4 in 144, or 1 in 36.

Each of the dice has 6 sides. There are 6 x 6 = 36 possible combinations. Of those, the following equal 5: 1 and 4 2 and 3 3 and 2 4 and 1 So the odds of rolling a 5 is 4 chances out of 36 4 / 36 = 1 / 9 That converts to a probability of 0.1111111...

6 sides on each dice. Each number on the sides is different, this represents the 1 out of all 6 amounts shown. So this is what you'll do for each dice... 1/6 + 1/6 = 2/6 = 1/3

It should be rolled in the direction as shown in the manual.

As shown in the manual

Direction shown in manual

in the direction shown in the manual

It is 3/8It is 3/8It is 3/8It is 3/8

It is malleability.

In the direction shown in the manual