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P(6) = 5/36 = 0.138888... ≈ 13.9%

When two fair dice are rolled, the sample space (all possible outcomes) has 36

equiprobable events:(1,1), (1,2), (1,3), (1,4), (1,5),(1,6), (2,1), (2,2), (2,3), (2,4),

(2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5),

(4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6).

There are 5 events where the sum of the dots of each die is equal to 6:

(1,5), (2,4), (3,3), (4,2), (5,1).

So in two fair dice are rolled the probability that the total number of spots shown is equal to 6 is, P(6) = 5/36 = 0.138888... ≈ 13.9%

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Q: If two fair dice are rolled what is the probability that the total number of spots shown is equal to 6?
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