If you mean x² + 9x +8 = 0
you use the quadratic equation.
Go the the Related links for a detailed explanation at Wikipedia.org, "The World's Encyclopedia"
x2 - 9x + 8 = (x-1)(x-8)
x2-9x+8=0 has two solutions:x = 8x = 1
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}
i thinking this answer should be -20
(x + 8)(x + 1)
x2 - 9x + 8 = (x-1)(x-8)
x2-9x+8=0 has two solutions:x = 8x = 1
(x-9)(x+9)
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}
i thinking this answer should be -20
If: y = x2-7x+8 and y = -x2+9x-6 Then: x2-7x+8 = -x2+9x-6 So: 2x2-16x+14 = 0 => x2-8x+7 = 0 Therefore: x = 1 and x = 7 By substitution: x =1, y = 2 and x = 7, y = 8 Points of intersection: (1, 2) and (7, 8)
(x + 8)(x + 1)
(x + 8)(x + 1)
x2+9x=-8 or x2+9x+8=0 (x+8)(x+1)=0 x=-8,-1 check answer: (-8)2+9(-8) = -8? and (-1)2+9(1) = -8? 64 - 72 is equal to -8. 1 - 9 is equal to -8. x= -8 and x= -1 are both solutions.
9x + 4 - x + 8 = 8x + 12
44 = 9x +8 36=9x 4=x
The slope is 0.