0
What else can I help you with?
Is the y3 equals x is linear function?
no
X y 3 equals x y3?
If one of them and the other One is exactly the same(capital,letters) then it is equal:D
If SinA equals minusxdividedy then cosA equals?
sin A = -x/y Since the sine is the ratio of the opposite leg to the hypotenuse, let's assume the opposite leg's length is -x and the hypotenuse's length is y. Let's call the adjacent leg's length z. So: (-x)2+z2=y2 z2=y2-(-x)2 z2=y2-x2 z=√(y2-x2) cos A = z/y = √(y2-x2)/y
If a plus b plus c equals x plus y plus z then prove a2 plus b2 plus c2 equals x2 plus y2 plus z2?
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
What does xyz equals if x1.2 y3 and z04?
If you know the values, just multiply them. "xyz" refers to the product of x, y, and z.
If y equals 3 then y3 y3-y equals?
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
Is the y3 equals x is linear function?
no
X y 3 equals x y3?
If one of them and the other One is exactly the same(capital,letters) then it is equal:D
If SinA equals minusxdividedy then cosA equals?
sin A = -x/y Since the sine is the ratio of the opposite leg to the hypotenuse, let's assume the opposite leg's length is -x and the hypotenuse's length is y. Let's call the adjacent leg's length z. So: (-x)2+z2=y2 z2=y2-(-x)2 z2=y2-x2 z=√(y2-x2) cos A = z/y = √(y2-x2)/y
If a plus b plus c equals x plus y plus z then prove a2 plus b2 plus c2 equals x2 plus y2 plus z2?
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
What does xyz equals if x1.2 y3 and z04?
If you know the values, just multiply them. "xyz" refers to the product of x, y, and z.
What is the answer to y2 x y?
Y3
How do you factor x to the sixth minus y to the sixth?
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
What is x12multiply y3 multiply y3 multiply x-2 equal?
12x2 - 24x + 9y
What is the evaluated number of the number x-y3 when x equals -10 and y equals -3?
Assuming that your question is x - y^3 Then you would do the following: x = -10 y = -3 -10 - (-3)^3 -10 - (-27) -10 + 27 = 17
What is another way to write x2 over y3?
x^2/y^3 = x^2*y^(-3)
What is the terms that include the same variable?
Not sure. There is no particular name for x2 and 2xy (both include x) in x2 + 2xy + y2 + y3
