x= z2 - 3
Wiki User
β 14y agono
If one of them and the other One is exactly the same(capital,letters) then it is equal:D
sin A = -x/y Since the sine is the ratio of the opposite leg to the hypotenuse, let's assume the opposite leg's length is -x and the hypotenuse's length is y. Let's call the adjacent leg's length z. So: (-x)2+z2=y2 z2=y2-(-x)2 z2=y2-x2 z=√(y2-x2) cos A = z/y = √(y2-x2)/y
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
If you know the values, just multiply them. "xyz" refers to the product of x, y, and z.
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
no
If one of them and the other One is exactly the same(capital,letters) then it is equal:D
sin A = -x/y Since the sine is the ratio of the opposite leg to the hypotenuse, let's assume the opposite leg's length is -x and the hypotenuse's length is y. Let's call the adjacent leg's length z. So: (-x)2+z2=y2 z2=y2-(-x)2 z2=y2-x2 z=√(y2-x2) cos A = z/y = √(y2-x2)/y
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
y^3
OK< SO< there are many problems that make the answer 38. A few examples:p-36= 74 where "p" equals 38.x+(-19) = 19 where "x" equals 38.i + 5783 = 5821 where "i" equals 38.94 - 56 - x where "x" equals 38.h +3 = 41 where "h" is equal to 38.y3 +19 = 54891 where "y3" equals 54872 where plain "y" would equal 38 (38x38x38 = 54872).And you could come up with a tON more, but that is some possible ones.
If you know the values, just multiply them. "xyz" refers to the product of x, y, and z.
Assuming that your question is x - y^3 Then you would do the following: x = -10 y = -3 -10 - (-3)^3 -10 - (-27) -10 + 27 = 17
Y3
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
Not sure. There is no particular name for x2 and 2xy (both include x) in x2 + 2xy + y2 + y3