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What is the domain and range yx2?
y=x^2
What is the answer to y2 x y?
Y3
What is another way to write x2 over y3?
x^2/y^3 = x^2*y^(-3)
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
What is the answer to x plus y to 3rd power plus x minus y to 3rd power?
(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
If y equals 3 then y3 y3-y equals?
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
What is the domain and range yx2?
y=x^2
What is the answer to y2 x y?
Y3
How do you factor x to the sixth minus y to the sixth?
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
How many roots does yx2-2x plus 1 have?
If you mean y = x^2 -2x +1 then it has two equal roots of 1 when y = 0
What is another way to write x2 over y3?
x^2/y^3 = x^2*y^(-3)
Determine autocorrelation function of yx2?
y - x = 2 y= -2x + 1
What is the answer x-y3 3x y 1?
6x+y=3
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
Factor completely x3-y3?
(x - y)(x^2 + xy + y^2
What is the answer to x plus y to 3rd power plus x minus y to 3rd power?
(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
How do you factor x3 - y3?
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