x + 5y = 0 so x = -5y or y = -x/5 You can express x in terms of y or y in terms of x but it is not possible to solve a single linear equation in two variables.
1/x = 1/y + 1/zx = ( yz ) / (y + z)
It cannot be done because the base for the second log is not given.
x= z2 - 3
9
x + 5y = 0 so x = -5y or y = -x/5 You can express x in terms of y or y in terms of x but it is not possible to solve a single linear equation in two variables.
1/x = 1/y + 1/zx = ( yz ) / (y + z)
It cannot be done because the base for the second log is not given.
To solve for two unknowns (x and y) you need two independent equations. All that you can do with the above is to express x in terms of y, as follows: 3X + 5Y = 7 => 3X = 7 - 5Y or X = (7 - 5Y)/3 or you can express y in terms of x: Y = (7 - 3X)/5
x= z2 - 3
9
To solve for two unknowns (x and y) you need two independent equations. All that you can do with the above is to express x in terms of y, as follows: 5x + 5y = -7 x + y = -7/5 x = -7/5 -y Similarly, you could express y in terms of x as: y = -7/5 -x IF, you had a value for either x or y from some other equation (or other source), you could substitute that value in either of these equations to solve for the other.
y * (x-1) = z Express as x,divide both sides by y(x - 1) = z/yadd 1 on both sidesx = z/y + 1
x = 6y over (y-6)
Yes: it is already in terms of y so nothing needs to be done.
y = x + 2 y = 2 - x so x + 2 = 2 - x Combining like terms: 2x = 0 so that x = 0 and then, from the first equation, y = 2
2sin(y) = 2x/sqrt(1+x^2)