It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
x - y = xydifferentiating wrt x1 - (dy/dx) = x(dy/dx) + y(x + 1)(dy/dx) + y + 1 = 0
x1:y1 = x2:y2 4:-2 = x2:5 x2 = (4*5)/-2 x2 = -10
x has been increased by times 1.625 So: 8*1.625 = 13 which is the value of y when x is 117
c
It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
x - y = xydifferentiating wrt x1 - (dy/dx) = x(dy/dx) + y(x + 1)(dy/dx) + y + 1 = 0
x1:y1 = x2:y2 4:-2 = x2:5 x2 = (4*5)/-2 x2 = -10
If x+y = 3 and y times x = 2 then y = 1.
use the formula y-y1=m(x-x1)
(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1
Use the point-slope form: y - y1 = m(x - x1). From the givens, y1 = 2, x1 = 9, and m = -2. Thus, y - 2 = -2(x - 9) = -2x + 18, or y = -2x + 20.
x has been increased by times 1.625 So: 8*1.625 = 13 which is the value of y when x is 117
c
y - y1 = m(x - x1), where m is the slope of the line, and (x1, y1) is a point on the line.
y-y1=m(x+x1)
'x' percent of 'y' = [ 0.01x times y ] .