If you reduced the volume by 0.25 then the answer is evident. Your question is very vague... If you reduced the length of one side to 3/4 it's origional... volume decrease to 33/43 or 27/64 (under half) This is because volume is proportional to length cubed. If you reduced the area of one side to 3/4 it's origional... volume would decrease to 33/2/43/2 (about 65% origional) This is because volume is proportional to length cubed and area is proportional to length squared.
You can calculated reduced volume by getting the starting volume and subtracting it from the finished volume For example, If I had 890ml of water and I had 155ml left, How much has the volume reduced by. 890 - 155 = 735. So the answer would be that the water has been reduced by a total of 735ml.
If the marbles are identical, the volume is the same. If you want, you can use different units and it looks like the volume is different.
Yes. A good example would be styrofoam and steel. The same volume of each of these substances would make for vastly different weights.
While a pound is a measurement of weight, a quart is a measurement of volume. The density and size of an item would be needed to find the weight of a specific volume.
The volume is reduced by 7/8. for example - if you had a cube measuring 4 cm each side - the volume would be 4x4x4=64cm3. Halving each side to 2cm would result in the sum 2x2x2=8cm3. 8 is one-eighth of 64.
Assuming it's a bag of gas at constant temperature, four times the volume by the relationship: P1V1 = P2V2
You can calculated reduced volume by getting the starting volume and subtracting it from the finished volume For example, If I had 890ml of water and I had 155ml left, How much has the volume reduced by. 890 - 155 = 735. So the answer would be that the water has been reduced by a total of 735ml.
To find the density of a quarter, you would first measure its mass using a scale. Then, you would measure its volume by water displacement, where you would measure the amount of water the quarter displaces when submerged. Finally, divide the mass by the volume to calculate the density of the quarter.
This is the reduction of volume to one-third.
To find the density of a quarter, you would need to determine its mass and volume. You can then divide the mass of the quarter by its volume to calculate its density. The density of a quarter may vary slightly depending on the specific composition and minting process used for that particular coin.
The volume would be reduced by a factor of 64.
The radius of a U.S. quarter is about 0.478 inches. The thickness of a U.S. quarter is about 0.069 inches. Being cylindrical, the volume of the quarter will be πr2h: v = πr2h ∴ v ≈ 3.142 × (0.478")2 × 0.069" ∴ v ≈ 0.488 cubic inches. All you need to do then is divide volume of the cylinder by the volume of the quarter: 169.56 / 0.488 ≈ 345.41 So it would take about 346 US quarters to fill such a cylinder.
The volume of the cylindrical barrel would decrease since the volume of a cylinder is directly proportional to its height. The volume would decrease by a factor of 9/16, since volume is calculated by multiplying the base area (πr^2) by the height.
If the volume of the container is reduced to one-half of its original size, the pressure will increase proportionally according to Boyle's Law. So if the original pressure was 10 psi, then the new pressure would be 20 psi when the volume is reduced by half.
If the marbles are identical, the volume is the same. If you want, you can use different units and it looks like the volume is different.
well the volume of an octagon would be different for every octagon.
The volume of the gas would decrease by half as well according to Charles's Law, which states that the volume of a gas is directly proportional to its Kelvin temperature when pressure is constant. If the Kelvin temperature is reduced to half its original value, the volume of the gas will also be reduced by half.