Best Answer

1/6x1/6 (the 4's) x(5/6x8) (the other 8) =1/36x(5/6x8)

=1/36x(5/6x8/1)

=1/36x40/6

=40/216

=10/59

Q: If you roll a die 10 times what's the probability of getting a 4 two times?

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1 out of 6 times,or 16.67% probability.

It is 0.9034, approx.

1 in 36

1/12

The probability of getting a sum of 2 at least once is 0.8155

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1 out of 6 times,or 16.67% probability.

It is 0.9034, approx.

1 in 36

1/12

0.3 * 0.3 = 0.09

The probability of getting a sum of 2 at least once is 0.8155

I'm assuming you're looking for the probability that you roll either a one or six at least once. So the problem can be rewritten as: 1 - probability of rolling 60 times and never getting ones or sixes = 1 - (2/3)^60

The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954

The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.

One.

there is 0% probability, unless you are some super nerd, and calculate the chance of it splitting the six and you getting two threes in one roll :p

The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.