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How do you find final velocity given mass of both objects and there initial velocities and one of their final velocities?
Suppose the two masses are m1 and m2. Their initial velocities are u1 and u2 and final velocities are v1 and v2. Then, using conservation of momentum. m1*u1 + m2*u2 = m1*v1 + m2*v2 Both m1 and m2 are given. Their initial velocities u1 and u2 are given and one of the two final velocities v1 and v2 is given which leaves only one unknown. So substitute all those values and calculate away.
What is the sum of all the multiples of 7 between 3 and 1298?
first you find the first term which is multiple of 7 which is 7 then you find the last term which is multiple of 7 is 1295 then we find n (number of terms) from the formula Un=U1+(n-1)d Un= last term,U1= first term,n= number of terms,d=the difference between a term and the term after it which in this case is 7 1295=7+(n-1)7 1295= 7+7n-7 1295=7n 185=n now we have every value we need so we apply them in the formula Sn=n/2(U1+Un) "this formula can be applied only in arithmetic sequence" =185/2(7+1295) = 120435
How do you Find the 75th term in the geometric sequence 3 12 48?
U2/U1 = 4 So Un = 3*4n-1 and therefore, U75 = 3*474 = 1.0704*1045 approx.
What are the uses of a linear air track?
A linear air track is typically used in the study of motion in physics. Depending of the different tracks available, different experiments can be conducted. These range from proving the conservation of momentum (m1*u1 + m2*u2 = m1*v1 + m2*v2), to finding the rate of acceleration (a = difference in velocity/difference in time).
What is the sum of a 6-term geometric series if the first term is 21 and the last term is 352947?
U1 = a = 21U6 = ar5 = 352947where Un is the nth term, with first term, a, and commn ratio r.Dividing the second equation by the first, r5 = 16807Taking the fifth root, r = 7.The S6 = a*(r6 - 1)/(r - 1) = 21*(76-1)/(7-1) = 411768
