Suppose the two masses are m1 and m2. Their initial velocities are u1 and u2 and final velocities are v1 and v2. Then, using conservation of momentum. m1*u1 + m2*u2 = m1*v1 + m2*v2 Both m1 and m2 are given. Their initial velocities u1 and u2 are given and one of the two final velocities v1 and v2 is given which leaves only one unknown. So substitute all those values and calculate away.
first you find the first term which is multiple of 7 which is 7 then you find the last term which is multiple of 7 is 1295 then we find n (number of terms) from the formula Un=U1+(n-1)d Un= last term,U1= first term,n= number of terms,d=the difference between a term and the term after it which in this case is 7 1295=7+(n-1)7 1295= 7+7n-7 1295=7n 185=n now we have every value we need so we apply them in the formula Sn=n/2(U1+Un) "this formula can be applied only in arithmetic sequence" =185/2(7+1295) = 120435
U2/U1 = 4 So Un = 3*4n-1 and therefore, U75 = 3*474 = 1.0704*1045 approx.
A linear air track is typically used in the study of motion in physics. Depending of the different tracks available, different experiments can be conducted. These range from proving the conservation of momentum (m1*u1 + m2*u2 = m1*v1 + m2*v2), to finding the rate of acceleration (a = difference in velocity/difference in time).
The answer will depend on what you mean by DO. An arithmetic sequence depends on two numbers: the seed, a, and the difference, d.The first number in the sequence is the seed and each number is obtained from the previous one by adding the difference.So U1 = aU2 = a + dU3 = U2 + d = a + d + d = a + 2dU4 = U3 + d = a + 2d + d = a + 3dand so on.In general, Un = a + (n - 1)*d
in season 1 he wears what appears to be a Sinn U1 on a green zulu strap.
U3 l2 d1 r1 u1 l3 d1 l1 d3 r4 u1 r1 u2 r1 u1 l2 d1 r1 d2 l1 d1 l4 u3 r4 u1 r1 d1 l3 u1 r2 d1 l4 d1 l2 u1 r6 l4 d3 l1 u1 d1 r3 u1 l1 d1 l3 u3 r2 d2 r2 d1 r2 u1 l4 u2 l2 d2 r1 l1 u1 r1
D1, l2,u1,r1,u1,r3,d1,r1,d3,l1,u2,l1,u1,d3,l1,u1,l1.
U3 L2 D1 R1 U1 L3 D1 L1 D3 L1 U1 D1 R3 U1 L2 D1 R4 U1 R1 U2 R1 U1 L2 R1 D3 L1 D1 L4 U3 R4 U1 R1 D1 L3 U1 R2 L3 D1 L1 D3 L2 U3 R6 L6 D1 R1 D1 L1 D1 R1 U1 R3 D1 R2 U1 L3 xauyala
Level 35: D1 L1 D1 L1 R1 U2 L1 D1 R1 D2 L1 D1 L4 U2 R2 U1 R2 U1 R1 D1 L3 D1 L2 D2 R4 U2 D2 L4 U2 R2 U1 R2 L2 U1 L2 D1 U1 R2 D1 R2 D3 L3 U1 D1 R1 U1 D1 R2 U1 R2 D1 L2 U4 R2 D1 L1 U1 L1 D1 L2 U1 L2 D1 R2
== == A random sample of 15 observations from the first population revealed a sample mean of 350 and a sample standard deviation of 12. A random sample of 17 observations from the second population revealed a sample mean of 342 and a sample standard deviation of 15. At the .10 significance level, is there a difference in the population means? ***Please show all the steps and work you used to conclude an answer and explain it as you would to a simpleton. Thank you so much. Read more: http://www.justanswer.com/questions/h0ee-null-hypothesis-h0-u1-u2alternate#ixzz0N7q0A7Ns
L1 U1 L2 D2 R1 D2 L1 U1 L5 R1 D2 L1 U1 L2 D1 R1 D3 L1 D2 R1 U1 R4 D2 U1 R2 D1 R2 U1 L1 U1 R5 D1 R1 U9 D8 L6 U2 L1 U3 R1 U3 L2 D2 L3 D1 L2 D4 L1 D2 R1 U1 R4 D1 R3 D1 R1 U1 L1 U1 R5 D1 R1 >>> Just like this set them one by one in the correct sequence. xauyala
U1, l2, d1, l1,u1, l2, d3, r1, d1, r2, u1, l2, r1, u2, r1, u1, l2, r1, d1, l1, r1, d3, r3, u1, l2, d1, l1, u3, r1, u1, l1, r3, d1, l3, r2, d2, r1, d1, l3, u3, r1, d1,r1, d1, l2
10 consecutive even numbers can be arranged in pairs of U1-U10, U2-U9, U3-U8, U4-U7 and U5-U6. Each pair MUST add to the same amount. [U1-U10 must be the same as U2-U9 because U2 is two more than U1 while U9 is two less than U10] So each pair must be 70/5 = 14 Now U10 = U1 + 2*9 = U1 + 18 So U1 + (U1 + 18) = 14 ie 2*U1 = -4 or U1 = -2 So the numbers are -2, 0, 2, 4, ... , 16
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R3, D2, R2, U2, L3, R2, U2, L4, D3, U3, R4, D2, L3, R3, U2, L4, D2, L1, D1, R1, U1, R1, D1, U1, R5, U1, L1, D1, L5, U2, R4, D1, U1, L4, D2, R3, D2, R2, U2, L4, R3, U2, L4, D2, L1, D1, R1, U1, R5, D2, L1, U1, R1, U1, L4, R3, U2, L4, D2
L2,R1,L3,U4,R1,D3,R1,U3,D3,U1,D1,R1,U3,R1,D3,R1,U3,D3,R1,U3,R3,D1,L2,D1,R2, D4,L1,U3,L1,D3,L1,U4,D3,L1,U3,L1,D2,U1,L1,D1,L1,U1,L1,D1,L1,U1,L1,D1,R1,D1,L1,D1,R1,U1,R1,D1,U1,R1,D1,R1,U1,R2,D1,L1.Good...