The two digit numbers in which the tens digit is five greater than the units digit are:
The number we are looking for is ten times the sum of its digits, and so must be a multiple of 10. The only one of the above numbers which fits this is 50, as 5 is five greater than 0, and 50 = 10 x (5+0).
3 and 6
5.723961 x 106 Unless you are told to round to a certain number of digits, you include all of the digits in this number because they are all significant.
88
55 52+52 = 50
81.
63
3 and 6
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
34.
81
-- "The sum of a two-digit number" is unclear. I took it to mean"The sum of the digits of a two-digit number."-- "... the product ?" is unclear. Are you looking for the product of the two digits,or the product of the forward and backward numbers ?-- It's not possible to write a number whose two digits sum to 12 and whosereverse exceeds it by 25. The tens digit would have to be 4.611... and the unitsdigit would have to be 7.388... .Then(4.611...) + (7.388...) = 12(46.111...) + (7.388...) = 53.5(73.888...) + (4.611...) = 78.5Difference = 25So, the number can't be written, but ...The product of its two digits is 34.071 (rounded)The product of the forward and reverse numbers is 4,199.75 (rounded)
Self complimentary codes are codes which after certain number of digits extends itself by taking the compliment of the previous digits.
5.723961 x 106 Unless you are told to round to a certain number of digits, you include all of the digits in this number because they are all significant.
88
55 52+52 = 50
The number is either 16, 25, 34, 43, 52, 61 or 70
81.