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Yes, the perpendicular bisector of a cord is the shortest distance from the centre of a circle to the cord.

Q: Does the perpendicular bisector of a cord of a circle passe through the center of the circle?

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Start with constructing a circle, then make a diameter from that circle. After you've done that, construct the perpendicular bisector of, the diameter, then draw the line in from the perpendicular bisector. After you've done that, connect the 4 points you have on the circle... then you're done. ^^ Hope this helps. :)

Let us assume you have a circle drawn with the center identified. Then draw one straight line through the center. Measure the length of the line bound by the intercepts of the straight line with the circumference of the circle. The line segment is the diameter. Another case would be that you have a circle drawn with no center marked. Draw one straight line through the circle. Use a compass to draw the perpendicular bisector of the line segment bound by the intercepts of the straight line with the circumference of the circle toward the inner circle (the center of a circle cannot lie outside the circle!). Repeat drawing another (different) straight line through the circle and finish with a perpendicular bisector. The two bisectors will intercept at the center of the circle. Then you can proceed the same way as described in the first paragraph above. Hint to draw a perpendicular bisector of a line segment: take one end of the compass, pivot the point at one end of the line segment and mark an arc with the other end on both sides of the line. Move the compass and pivot one point at the other end of the line segment. Mark an arc with the other end on both sides of the line. If the procedure is done correctly, the two arcs, one from each end, should intercept on one side of the line. There is another intercept of the two arcs on the side of the line. Connect the two arc-intercepts with a straight line. Convince yourself that the line bisects the straight line at a right angle. This last line is the perpendicular bisector of the original line (The first and last lines form the perpendicular bisector of one another). ===================

1) draw the circle with a radius r and the center at O. 2) mark a point, A, on the circle 3) draw a line from O to A and beyond to point B, a little longer than the radius 4) draw a perpendicular bisector at point A using line OB 5) the perpendicular bisector is the tangent at point A In case, you forgot about drawing the perpendicular bisector. Here is the procedure: a) use your compass and mark equidistant points C and D from point A on line OB (make the length slightly less than half the radius); one point should be outside the circle and the other within. b) use your compass and draw an arc from point C and then from point D, with the arc radii being identical and about as long as the circle radius; the two arcs should intercept at two locations, E and F, one on each side of line OA. c) join points E and F to form the perpendicular bisector of line CD ===============================

Points equidistant from AB lie on its perpendicular bisector. Points 5 inches from A lie on the circle with centre A and radius = 5 inches. You will have two points where the perp bisector and circle intersect.

the tangent will never go through the center of a cirlce. The tangent is, by definition, a line that only intersects the circle at one point. If you look down a pencil along its long axis, so that it appears to be a circle, and place your finger on top of and perpendicular to the pencil, your finger is now tangent to the circle you see.

Related questions

A circle can have perpendicular bisector lines by means of its diameter.

A circle cannot form a perpendicular bisector.

Yes. The perpendicular bisector of a chord forms a radius when extended to the centre of the circle and a diameter when extended beyond the centre to the opposite point on the circumference.

The perpendicular bisector of ANY chord of the circle goes through the center. Each side of a triangle mentioned would be a chord of the circle therefore it is true that the perpendicular bisectors of each side intersect at the center.

You have points A, B, and C. Using a compass and straight edge, find a perpendicular bisector of AB (that is, a line that is perpendicular to AB and intersects AB at the midpoint of AB. Next, find a perpendicular bisector of BC. The two lines you found will meet at the center of the circle.

A circle cannot form a perpendicular bisector.

Perpendicular bisector lines intersect at right angles

-- Draw any two random chords of the circle. -- Construct the perpendicular bisector of each chord. -- The perpendicular bisectors intersect at the center of the circle. All of this can be done with a compass, an unmarked straight-edge, and a pencil.

Draw a line from any part on the outside of a circle to the exact center of the circle. * * * * * That is fine if you know where the center is but not much use if you are just given a circle and do not know where the exact centre is. In this case: Draw a chord - a straight line joining any two points on the circumference of the circle. Then draw the perpendicular bisector of the chord. Draw another chord and its perpendicular bisector. The two perpendicular bisectors will meet at the centre.

A circle is a shape that has no particular direction. There is, therefore, no particular direction for anything to be perpendicular to. To that extent, this question is nonsense.Every diameter of a circle bisects it, so just draw any line through its centre!

Perpendicular bisector.

Draw a chord, then construct a line perpendicular to the center of the chord; it passes through the center of the circle. Do this again with a different chord and the intersection of the two perpendicular lines is the center of the circle.