Sin A must be a number whose absolute value cannot exceed 1 and so it cannot be 35.
Yes
No because these are the angles of a scalene triangle
Use the Law of Cosines: c^2 = a^2+b^2-2ab cos C. Here, the two legs of a triangle are both the radius (14 inches long), and the angle between them is 35 degrees. So c^2 = 14^2+14^2-2*14*14*cos 35 c^2 = 2*14^2(1-cos 35) c^2 = 70.89.. c = 8.42..
The angles of 35°, 55°, and 90° form a right triangle, as one of the angles is exactly 90°. The sum of the angles in any triangle is always 180°, and in this case, 35° + 55° + 90° equals 180°. This triangle is also classified as an acute triangle because the other two angles (35° and 55°) are both less than 90°.
It is: 37 units in length
Yes
acute
The right-angle triangle measures 28cm by 35cm. Such a triangle is half of a rectangle.Therefore 28 x 35 = 980cm2 is the area of a rectangle.980 / 2 = 490cm2 will give the area of the triangle (which is 490cm2).
A triangle whose sides are 16, 30, and 35 in length is not a right triangle, becausethe square of the length of the longest side is not equal to the sum of the squaresof the lengths of the other two sides.But if the 35 were a 34 instead, then it wouldbe.
No because it does not comply with Pythagoras' theorem.
It is a right angle triangle
In degrees? cos(35˚) = .81915, sin(24˚) = .40673;cos(35˚) * sin(24˚) = .33318In radians? cos(35) = -.90367, sin(24) = -.90558;cos(35) * sin(24) = .81836A calculator will achieve these results faster than wiki.answers. 9 times out of 10, at least.:-)
It is a right angle triangle because the 3rd angle is 90 degrees
No because these are the angles of a scalene triangle
question doesn't make sence but i sort of know what your getting at.if you have a right hand triangle and one of the other angles is 35 deg then what is the remaining angle's angle.all triangles angles added together come to 180dega right angle is 90degso 90 + 35 = 125180 - 125 = 55the remainding angle is 55deg.
180 degrees in a triangle 180 - 90 - 55 = 35 35 degrees
False because it does not comply with Pythagoras' theorem.