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Is the square root of a number always bigger than its square root?
No, not always since: if a number is more than 1, then its square root is smaller than the number. if a number is less than 1, then its square root is bigger than the number.
Is a square of a number always bigger than the number?
all of the numbers, except the numbers 1 and below
What is an example of a rational number between the negative square root of four and the square root of four?
-1,0,or 1 the negative square root of four is negative two and the square root of four is two
The square root of anumber x is always less than x?
No. The square root of any number between 0 and 1 is bigger than itself. For example, sqrt(1/4) = 1/2 or sqrt(1/9) = 1/3. The square roots of 0 and 1 are the same as the number itself. The square root of any number x that is bigger than 1 is less than x.
What is the biggest number smaller than the square of itself?
There is no biggest number.Any number greater than one is smaller than the square of itself.For example:5 < 25100 < 10000On the other hand, any number between 0 and 1 is greater than the square of itself:.5 > .25.6 > .36As we get closer and closer to 1, such as .9999 square which is =.99801, we note that the square get closer to the number and of course bigger too.So if we look at .99999992 we see it is very close to 1. The more 9's we add the closer we get to 1 and in fact and in fact an infinite number of 9's will be 1 one itself.But there is no "biggest number" that is less than 1. For any number you can think of that is between 0 and 1 (not including 1), it is possible to name a bigger number. This has to do with something called the density of the reals. Actually in this case it is the density of the rationals in the reals. Say you give me a number with a decimal and a million 9's to the left of the decimal, I just make it a million and one and my number is bigger and closer to the square.
