1/6 on the first roll, and 1/6 of rolling a six on the second roll. Overall, the chances of you rolling a 5 on the first and a six on the second is 1/3.
What is the probability of rolling a 6 the first time and a 1 the second time
None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12
The probability of rolling a 3 is 1/6. The probability of rolling a 6 is 1/6. There are two ways to roll a 3 and 6: roll 3 on the first die and 6 on the second or roll 6 on the first and 3 on the second. The probability of the first is 1/6 x 1/6 = 1/36. Likewise the probability of the second is 1/6 x 1/6 = 1/36. Combined you get 1/36 + 1/36 = 2/36 = 1/18
The probability of rolling a 2 or a 4 on the second die is independent of the outcome of the first die. A standard die has six faces, with three even numbers (2, 4, and 6). Therefore, the probability of rolling a 2 or a 4 on the second die is 2 out of 6, or 1/3, regardless of whether an even number was rolled on the first die.
The probability is 1 out of 36, or about 3%, I think.
What is the probability of rolling a 6 the first time and a 1 the second time
The probability of rolling a 2 on the first roll is 1 in 6. The probability of rolling a 3 on the second roll is 1 in 6. However, the probability of rolling a 2 on the first roll and 3 on the second roll before you roll at all is 1/6 x 1/6 = 1 in 36.
None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12
Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.
The probability of rolling a 3 is 1/6. The probability of rolling a 6 is 1/6. There are two ways to roll a 3 and 6: roll 3 on the first die and 6 on the second or roll 6 on the first and 3 on the second. The probability of the first is 1/6 x 1/6 = 1/36. Likewise the probability of the second is 1/6 x 1/6 = 1/36. Combined you get 1/36 + 1/36 = 2/36 = 1/18
The probability of rolling a 2 or a 4 on the second die is independent of the outcome of the first die. A standard die has six faces, with three even numbers (2, 4, and 6). Therefore, the probability of rolling a 2 or a 4 on the second die is 2 out of 6, or 1/3, regardless of whether an even number was rolled on the first die.
The probability is 1 out of 36, or about 3%, I think.
1/6 + 1/6 = 1/3
Of all the six numbers on a cube, only the '5' is not a factor of 12.Probability of rolling a factor of 12 on the first cube = 5/6 .Probability of rolling a factor of 12 on the second cube = 5/6 .Probability of rolling a factor of 12 on both cubes = (5/6 x 5/6 ) = 25/36 = 694/9 %.
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
The probability of rolling a 3 on a single die is 1/6. Similarly, the probability of rolling a 5 on a single die is also 1/6. When rolling the die twice, the probabilities are independent events, so you multiply the probabilities together: (1/6) * (1/6) = 1/36. Therefore, the probability of rolling a 3 the first time and a 5 the second time is 1/36.
The probability of throwing just one one with two dice can be calculated by considering the different ways it can occur. There are two ways to get one one: rolling a one on the first die and any number on the second die, or rolling any number on the first die and a one on the second die. There are a total of 36 possible outcomes when rolling two dice, so the probability is 2/36, which simplifies to 1/18.