The probability of rolling a 2 on the first roll is 1 in 6. The probability of rolling a 3 on the second roll is 1 in 6. However, the probability of rolling a 2 on the first roll and 3 on the second roll before you roll at all is 1/6 x 1/6 = 1 in 36.
36
50%
1/36
1/36
It is 1/6.
It is 4/36 or 1/9.
2/9
If they are normal cubes, the probability is 1, if you roll them often enough.
If I understand the question correctly, you want the probability of each cube showing an odd number. If the number cubes are fair, then the answer is 1/4.
it is all about chance my dear girl/boy but most likely a 1.98007657 chance
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The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36