x3+8y3 = (x+2y)(x2-2xy+4y2)
The discriminant of the quadratic factor is 4y2-16y2 < 0 so there are no real roots.
So the only real root of the original polynomial is x+2y=0 or x = -2y
105 squared plus 8 cubed is equal to 11,537.
The polynomial IS b2 - 6b + 8.
The answer is 537
To find the sum of 2 cubed, 3 cubed, and 4 cubed, we calculate each value: (2^3 = 8), (3^3 = 27), and (4^3 = 64). Adding these together gives (8 + 27 + 64 = 99). Therefore, (2^3 + 3^3 + 4^3 = 99).
2 cubed = 8 8 cubed = 512
2 cubed = 2*2*2 =8. 8+8+8= 24
105 squared plus 8 cubed is equal to 11,537.
The polynomial IS b2 - 6b + 8.
(x-3)(x+8)
The answer is 537
13
To find the sum of 2 cubed, 3 cubed, and 4 cubed, we calculate each value: (2^3 = 8), (3^3 = 27), and (4^3 = 64). Adding these together gives (8 + 27 + 64 = 99). Therefore, (2^3 + 3^3 + 4^3 = 99).
X3 + 8= (x+2)(x2-2x+4)
2 cubed = 8 8 cubed = 512
(2x + 5)(4x^2 - 10x + 25)
the answer is (3x-2)(9x squared+6x+4)
2 cubed = 8