2 cubed = 2*2*2 =8. 8+8+8= 24
a(a^2 + 1)
To find the sum of 2 cubed, 3 cubed, and 4 cubed, we calculate each value: (2^3 = 8), (3^3 = 27), and (4^3 = 64). Adding these together gives (8 + 27 + 64 = 99). Therefore, (2^3 + 3^3 + 4^3 = 99).
(y + 27)(y^2 - 27y + 729)
(y + 3z)(y^2 - 3yz + 9z^2)
Helen is an ashole
Answer: 12
2(x^2 + 2)(x + 3)
2(x^2 + 2)(x + 3)
17 squared is 289. 85 cubed is 614,125. 614,125 times 2 is 1,228,250. 1,228,250 plus 289 is 1,228,539.
3-cubed plus 2 plus 1 plus 4= 34
x^3 + y^3 = (x + y)(x^2 - xy + y^2)
x(x^2 + 1)