It seems like there's a typo in your equation. If you meant (x + 2y = 13), you can use the substitution method by solving for (x) in terms of (y). Rearranging gives (x = 13 - 2y). You can then substitute this expression for (x) into another equation if you're solving a system of equations.
2x-3y=13
If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3
-2
x+y=5
If you mean x+2y = -2 and 3x+4y = 6 then by solving the simultaneous equations by substitution x = 10 and y = -6
If you mean: y = 6x+11 and y = 2x+7 Then by substitution: x = -1 and y = 5
2x-3y=13
If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3
If you mean: -x+3y = 6 and x+3y = 18 then by substitution x = 6 and y = 4
Substitution method: y = 1 + x so 2x + (1 + x) = 4, ie 3x = 3 so x = 1 and y = 2
-2
x+y=5
x+2(x+3) = 12 x+2x+6 = 12 x+2x = 12-6 3x = 6 x = 2 and y = 5
(2,3)
If you mean x+2y = -2 and 3x+4y = 6 then by solving the simultaneous equations by substitution x = 10 and y = -6
Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
X = 135 and y = 15 Solved by addition and substitution