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5 marbles. 3 red marbles, 2 white marbles.

The probability of drawing a white marble is P(W) = 2/5 = 0.40

If the white marble is not returned to the rest of the marbles (no substitution), the

probability that the second marble drawn is a red one is P(R) = 3/4 = 0.75.

The probability that the event of drawing first a white marble and without substitution

the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/4) = 6/20 = 3/10 = 0.30 = 30.0%.

If the process of drawing the marbles is with substitution, the probability of the

second draw turning a red marble is P(R) = 3/5 = 0.60 = 60.0%

The probability that the event of first drawing a white marble and after returning the

marble back to the original group of marbles (with substitution) the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/5) = 6/25 = 0.24 = 24.0%.

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Q: What is the probability of drawing a white marble then a red marble if there are 3 red marbles and 2 white marbles?
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