answersLogoWhite

0

5 marbles. 3 red marbles, 2 white marbles.

The probability of drawing a white marble is P(W) = 2/5 = 0.40

If the white marble is not returned to the rest of the marbles (no substitution), the

probability that the second marble drawn is a red one is P(R) = 3/4 = 0.75.

The probability that the event of drawing first a white marble and without substitution

the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/4) = 6/20 = 3/10 = 0.30 = 30.0%.

If the process of drawing the marbles is with substitution, the probability of the

second draw turning a red marble is P(R) = 3/5 = 0.60 = 60.0%

The probability that the event of first drawing a white marble and after returning the

marble back to the original group of marbles (with substitution) the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/5) = 6/25 = 0.24 = 24.0%.

User Avatar

Wiki User

13y ago

What else can I help you with?

Related Questions

What is the probability of drawing a marble that is not white?

It depends on how many marbles of each colour you have....


If a box contains 4 red marbles seven white and 5 blue and two marbles are drawn one at a time with replacement What is the probability that both marbles are white?

Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.


What are the odds in favor of choosing a white marble from a bag containing 3 black marbles 4 green marbles and 6 white marbles?

The probability of drawing a white marble is .46


The table below shows the number of marbles of different colors in a bag Marble Experiment Color of Marbles Number of Marbles Red 1 White 5 Black 10 Ursula draws a marble from the bag randomly without?

Ursula has a total of 16 marbles in the bag (1 red, 5 white, and 10 black). When she draws a marble randomly, the probability of drawing each color can be calculated based on their quantities. The probability of drawing a red marble is 1/16, a white marble is 5/16, and a black marble is 10/16. This means that black marbles are the most likely to be drawn, followed by white and then red.


What is the equation used to determine probability?

Number of possibilities for one category / Total of all possibilities. For example, if I had a bag of marbles where there are three white marbles and two black marbles. The probability of pulling out a white marble is how many white marbles are in the bag which is: three. But the total of things you can draw out of the bag can either be one of the three white marbles or one of the two black marbles. 3 white marbles+ 2 Black marbles= five marbles. Possibility is 3/5 for drawing a white marble.


A bag contains 3 white marbles 7 green marbles and 5 yellow marbles What is the probability of drawing a yellow marble?

5/15 = 1/3 = 33 and 1/3 percent


What is the probability of drawing 1 green then 1 blue marble from a bag with 5 blue marbles 5 red marbles 3 green marbles 2 white marbles?

hypergeom. f(1;13,3,1) * f(1;12,5,1)


A bag contains 4red marbles 2 white marbles a marble is selected kept out the bag and then another marble is selected what is the probability of selecting a red marble and then white marble?

2/6


Suppose you choose a marble from a bag with 3 red 3 white and 5 blue You return the first marble to the bag and then choose again find P Red then Blue Can anyone help me with this math question?

To find the probability of drawing a red marble first and then a blue marble, we first calculate the probability of each event separately. The probability of drawing a red marble is ( \frac{3}{11} ), since there are 3 red marbles out of a total of 11 marbles. After returning the red marble, the probability of then drawing a blue marble is ( \frac{5}{11} ). Therefore, the combined probability of drawing a red marble first and then a blue marble is ( \frac{3}{11} \times \frac{5}{11} = \frac{15}{121} ).


In a bag there are 4 red marbles 5 white marbles and 6 blue marbles once a marble is selected it is not replaced what are the odds of pulling a red marble than a white marble?

The odds of pulling a red marble on the first try is 4/15 or about .27 and the probability of drawing a white marble the second time if a the first is a red marble is 5/14 or about .36. the odds of both happening is the product of the probabilities of the other events, or 2/21.


A bag contains 6 purple marbles and 7 white marbles Two marbles are drawn at random One marble is drawn and not replaced Then a second marble is drawn What is the probability that the first marble?

There are 13 marbles in total. The order is specified.P(1st is white and the 2ndis purple) = (7/13)(6/12) = (7/13)(1/2) = 7/26.


If you have three marbles red white and blue what is the probability that you do not get a white or blue marble?

1 in 3