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To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as:
[ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ]
Without specific numbers, the exact probability cannot be computed.
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A bag has 13 green marbles What is the probability pf drawing out a green marble?
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
A bag contains 8 marbles 4 are blue 3 are green and one is orange you draw out one marble and then another without replacing the first marble Find the probability of drawing 2 blue marbles?
Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.
What is the probability of drawing a gray marble?
4 out of 7
A bag contains 5 red marbles 3 blue marbles and 1 green marble. A randomly drawn marble is not blue?
To find the probability of drawing a marble that is not blue, we first calculate the total number of marbles, which is 5 red + 3 blue + 1 green = 9 marbles. The number of marbles that are not blue is 5 red + 1 green = 6 marbles. Therefore, the probability of drawing a marble that is not blue is 6 out of 9, which simplifies to 2/3.
A bag has 13 green marbles What is the probability pf drawing out a green marble?
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
What is the theoretical probability of randomly drawing a green marble if there are 5 red marbles 8 blue marbles and 12 green marbles in a bag.?
The theoretical probability of randomly drawing a green marble can be calculated by dividing the number of green marbles by the total number of marbles in the bag. In this case, there are 12 green marbles out of a total of 5 red marbles + 8 blue marbles + 12 green marbles, which is 25 marbles in total. Therefore, the theoretical probability of drawing a green marble is 12/25 or 48%.
A bag contains 3 blue marbles 7 red marbles and 5 yellow marbles. If Joe picks 1 marble from the bag at random what is the probability that it will be blue?
A bag of marbles contains 13 marbles. 5 Blue, 3 Yellow, 4 Green and 1 Red. Leave all answers as a ratio in lowest terms. 18 points On a single draw, what is the probability of drawing a yellow marble? What is the probability of not drawing a yellow marble? What are the odds in favor of drawing a blue marble? What is the probability of drawing a red or yellow marble? What is the probability of drawing a purple marble? If you had to bet on drawing a marble of a certain color what color would you not choose?
A bag contains 8 marbles 4 are blue 3 are green and one is orange you draw out one marble and then another without replacing the first marble Find the probability of drawing 2 blue marbles?
Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.
A bag contains 6 red marbles 9 blue marbles and 5 green marbles You withdraw one marble replace it and withdraw another marble What is the probability that you do not draw two green marbles 25 denomo?
To calculate the probability of not drawing two green marbles, we first find the probability of drawing a green marble on the first draw, which is 5/20 since there are 5 green marbles out of a total of 20 marbles. The probability of not drawing a green marble on the first draw is 1 - 5/20 = 15/20. Since the marbles are replaced, the probability of not drawing a green marble on the second draw is also 15/20. Therefore, the probability of not drawing two green marbles is (15/20) * (15/20) = 225/400 = 9/16 or 56.25%.
What is the probability of drawing a gray marble?
4 out of 7
A bag contains 5 red marbles 3 blue marbles and 1 green marble. A randomly drawn marble is not blue?
To find the probability of drawing a marble that is not blue, we first calculate the total number of marbles, which is 5 red + 3 blue + 1 green = 9 marbles. The number of marbles that are not blue is 5 red + 1 green = 6 marbles. Therefore, the probability of drawing a marble that is not blue is 6 out of 9, which simplifies to 2/3.
What are the odds in favor of choosing a white marble from a bag containing 3 black marbles 4 green marbles and 6 white marbles?
The probability of drawing a white marble is .46
A bag contains 2 yellow 12 red and 6 green marbles What is the probability of selecting a red marble replacing it then selecting another red marble?
The probability of drawing two reds, with replacement, is the same as the probability of drawing a red, times itself. So: P(drawing two reds) = P(drawing a red)2 = (12/(2 + 12 + 6))2 = (12/20)2 = (3/5)2 = 9/25
Suppose you choose a marble from a bag with 3 red 3 white and 5 blue You return the first marble to the bag and then choose again find P Red then Blue Can anyone help me with this math question?
To find the probability of drawing a red marble first and then a blue marble, we first calculate the probability of each event separately. The probability of drawing a red marble is ( \frac{3}{11} ), since there are 3 red marbles out of a total of 11 marbles. After returning the red marble, the probability of then drawing a blue marble is ( \frac{5}{11} ). Therefore, the combined probability of drawing a red marble first and then a blue marble is ( \frac{3}{11} \times \frac{5}{11} = \frac{15}{121} ).
There are 9 red and 6 blue marbles in a jar If you draw red marbles from the jar 7 times what is the experimental probability of drawing a red marble?
The answer is dependent on whether of not you replace the marbles in the jar. If you do, the probability of drawing a red marble is 9 in 15 or 60%, every time. If you do not replace the marbles, the probability of drawing a red marble is 2 in 8 or 25%.
