As for example in the equation: y = 2x+5 the slope is 2 and the y intercept is 5
A vertical line can not be defined by any normal equation, because its range is a single number that gives the x-coordinate and y can have any value whatever.
To determine which points are on the line given by the equation ( y = 2x ), you can substitute the x-coordinate of each point into the equation and see if the resulting y-coordinate matches the point's y-coordinate. For example, if you have the point (1, 2), substituting ( x = 1 ) gives ( y = 2(1) = 2 ), so this point is on the line. Repeat this process for each point to find which ones satisfy the equation.
To determine if a point is a solution to the equation (y = 2x + 6), you need to substitute the x-coordinate of the point into the equation and see if the resulting y-value matches the y-coordinate of the point. For example, if the point is (1, 8), substituting (x = 1) gives (y = 2(1) + 6 = 8), which matches the y-coordinate, thus (1, 8) is a solution. You can repeat this process for any point to check if it satisfies the equation.
To find where the line ( y = 3x + 7 ) crosses the y-axis, set ( x = 0 ). Plugging this into the equation gives ( y = 3(0) + 7 = 7 ). Therefore, the line crosses the y-axis at the point ( (0, 7) ).
Yes, the coordinates for the vertex of a quadratic function in the form (y = ax^2 + bx + c) can be found using the formula (x = -\frac{b}{2a}) to determine the x-coordinate. Once you have the x-coordinate, substitute it back into the original equation to find the corresponding y-coordinate. This gives you the vertex in the form ((x, y)).
The slope intercept equation also called the y intercept equation. It isy=mx+b in which x and y are coordinates, m is the slope of the line, and b is the y-intercept. so b would be the y-coordinate that intersects the y-axis.
The point slope form of a line is the equation y-y_1=m*(x-x_1) where y_1 and x_1 are coordinate for some point the line intersect and m is the slope. Just plugging in your given numbers gives the equation y+4=-2*(x+8)
A vertical line can not be defined by any normal equation, because its range is a single number that gives the x-coordinate and y can have any value whatever.
To determine which points are on the line given by the equation ( y = 2x ), you can substitute the x-coordinate of each point into the equation and see if the resulting y-coordinate matches the point's y-coordinate. For example, if you have the point (1, 2), substituting ( x = 1 ) gives ( y = 2(1) = 2 ), so this point is on the line. Repeat this process for each point to find which ones satisfy the equation.
Th formul for slope-intercept is y=mx+b. y= the y-coordinate m= the slope x= the x-coordinate b= the y-intercept Therefore if your equation was y=3x+5 then the coefficient that gives the slope is 3.
To determine if a point is a solution to the equation (y = 2x + 6), you need to substitute the x-coordinate of the point into the equation and see if the resulting y-value matches the y-coordinate of the point. For example, if the point is (1, 8), substituting (x = 1) gives (y = 2(1) + 6 = 8), which matches the y-coordinate, thus (1, 8) is a solution. You can repeat this process for any point to check if it satisfies the equation.
Assuming that the horizontal axis is for a and the vertical axis is for b,Cover up 2a so you get the equation 3b = 6 which gives b = 2.Mark the point (0, 2) on the coordinate plane.Cover up 3b so you get the equation 2a = 6 which gives a = 3.Mark the point (3, 0) on the coordinate plane.Join the two points and extend the line in both directions.Done!
Substitute the x coordinate into the equation for x and calculate y. If the formla gives the same y value as the coordinates, the point is on the line. If it is diffent, it is not on the line.
To find where the line ( y = 3x + 7 ) crosses the y-axis, set ( x = 0 ). Plugging this into the equation gives ( y = 3(0) + 7 = 7 ). Therefore, the line crosses the y-axis at the point ( (0, 7) ).
Yes, the coordinates for the vertex of a quadratic function in the form (y = ax^2 + bx + c) can be found using the formula (x = -\frac{b}{2a}) to determine the x-coordinate. Once you have the x-coordinate, substitute it back into the original equation to find the corresponding y-coordinate. This gives you the vertex in the form ((x, y)).
An equation that relates x and y coordinates defines a specific relationship between the two variables, allowing you to determine the position of points on the xy-plane. For example, a linear equation like (y = mx + b) gives you the y-coordinate for any given x-coordinate, and vice versa. By substituting different values of x or y into the equation, you can generate a set of points that lie on the graph of the equation, illustrating the relationship visually on the plane. This ability to derive coordinates from an equation is fundamental in analyzing and graphing mathematical relationships.
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