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AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
If line BE is the bisector of segment AC, it means that BE divides AC into two equal segments. Therefore, if AB is 7, then AC must be twice that length, making AC equal to 14.
AC = sqrt(AB^2+BC^2) other wise known as a^2+b^2=c^2. Therefore AC is around 51.739
A mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/C