AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
AC = sqrt(AB^2+BC^2) other wise known as a^2+b^2=c^2. Therefore AC is around 51.739
A mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/C
a*(b+c)=ab+ac
If 2 segments have the same length they are known as 'congruent segments' IE: segment AB=segment AC (or AB=AC) then AB @ AC (or AB is congruent to AC)
yes because ab plus bc is ac
C is the midpoint of Ab . then AC = BC. So AC= CB.
.Ab + c cb + a
the midpoint of AB.
AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21
It can be simplified to -c-a-ac
If angle ACB is the right angle then ab is the hypotenuse. Then, (ab)2 = 62 + 92 = 36 + 81 = 117 ab = √117 = 10.8 (3 sf) If angle BAC is the right angle then ab is one leg of a right angled triangle with bc the hypotenuse. 92 = 62 + (ab)2 : (ab)2 = 92 - 62 = 81 - 36 = 45 ab = √45 = 6.71 (3 sf)
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
C is not on the line AB.
Assuming that AB and AC are straight lines, the answer depends on the angle between AB and AC. Depending on that, BC can have any value in the range (22, 46).
Zero.For instance, given a right triangle with points ABC. where AC is the hypotenuse, then to find the angle between AB, we take sin(AB/AC), where AB is the distance between points A and B, and AC is the distance between A and C. If we replace AB with 0, the equation would be sin(0/AC). Sine of zero is always zero.