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It seems that you are referring to specific figures that are not provided in your question. To determine in which figure AB equals AC, I would need to see the figures in question. Please provide additional context or describe the figures for a more accurate response.

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2w ago

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Write a porpotion that can be used to determine WZ using ratios between the two figures Then determine WC?

To determine WZ using ratios between two similar figures, you can set up the proportion as follows: ( \frac{WZ}{AB} = \frac{WX}{AC} ), where AB and AC are corresponding sides of the two figures. If you know the lengths of AB and AC, you can rearrange the equation to find WZ: ( WZ = \frac{WX \cdot AB}{AC} ). To determine WC, you would need to use a similar proportion involving the sides that relate to WC and the corresponding sides of the figures.


In triangle ABC side AB is 9 cm shorter than side AC while bc is 3cm longer than side AC if the perimeter is 48 cm find the lenghts of the three sides?

AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21


If Line BE is the bisector of segment AC. If AB 7 then AC how many units.?

If line BE is the bisector of segment AC, it means that it divides AC into two equal parts. Given that AB is 7 units, it implies that the length of AC is twice the length of AB. Therefore, AC is 2 × 7 = 14 units.


Why are there six trigonometrics functions only?

All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions


Line BE is the bisector of segment AC. If AB 7 then AC .?

If line BE is the bisector of segment AC, it means that BE divides AC into two equal segments. Therefore, if AB is 7, then AC must be twice that length, making AC equal to 14.

Related Questions

What are two segments that have the same measurement?

If 2 segments have the same length they are known as 'congruent segments' IE: segment AB=segment AC (or AB=AC) then AB @ AC (or AB is congruent to AC)


If ab plus bc equals ac then ac equals ab plus bc?

yes because ab plus bc is ac


If ac cb ab and ac cb then the point c is?

C is the midpoint of Ab . then AC = BC. So AC= CB.


What is the general form of a single-replacement reaction?

.Ab + c cb + a


If ac plus cb equals ab and ac equals cb then the point c is?

the midpoint of AB.


In triangle ABC side AB is 9 cm shorter than side AC while bc is 3cm longer than side AC if the perimeter is 48 cm find the lenghts of the three sides?

AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21


What is the answer for ab-c-ba-a-ac?

It can be simplified to -c-a-ac


If Line BE is the bisector of segment AC. If AB 7 then AC how many units.?

If line BE is the bisector of segment AC, it means that it divides AC into two equal parts. Given that AB is 7 units, it implies that the length of AC is twice the length of AB. Therefore, AC is 2 × 7 = 14 units.


Abc is a right angled triangle ac equals 6cm bc equals 9cm work out the length of ab give your answer to 3 sig figures?

If angle ACB is the right angle then ab is the hypotenuse. Then, (ab)2 = 62 + 92 = 36 + 81 = 117 ab = √117 = 10.8 (3 sf) If angle BAC is the right angle then ab is one leg of a right angled triangle with bc the hypotenuse. 92 = 62 + (ab)2 : (ab)2 = 92 - 62 = 81 - 36 = 45 ab = √45 = 6.71 (3 sf)


Why are there six trigonometrics functions only?

All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions


If ac CB and gt AB then point C is?

C is not on the line AB.


If AC plus CB AB and AC CB then point C is?

If AC plus CB equals AB and AC is equal to CB, then point C is the midpoint of segment AB. This means that point C divides the segment AB into two equal parts, making AC equal to CB. Therefore, point C is located exactly halfway between points A and B.