For the equation 3x-5=8x-30, the first thing you do is subtract 3x from both sides of the equation, so you get -5=5x-30. Next you add 30 to both sides, getting 25=5x. Lastly, you divide both sides by 5, leaving the solution of 5=x. Should your equation be 3(x-5)=8x-30, you would first multiply x-5 by 3, getting 3x-15, creating the equation 3x-15=8x-30. You would then subtract 3x from both sides, betting -15=5x-30. Then add 30 to both sides, creating an equation of 15=5x. Divide both sides by 5, and you get a solution of 3-x.
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Not necessarily, take for example the equation x^2=5-12i. Then, 3-2i satisfies the equation. However, 3+2i does not because (3+2i)^2 = 5+12i.
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
Yes, because the equation is linear, there is only one solution:4x - 3 = 12 +2x4x - 2x = 12 + 32x = 15x = 7.5There is no other solution
The solution to the equation 0.81y + 3x is 3(0.27y + x).
2 is a solution of the equation, but not if it's an inequality.