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To simplify the expression ((10x \cdot 36y) \cdot (2x \cdot y)), you multiply the coefficients and the variables separately. This results in (20x^2 \cdot 36y^2) which simplifies to (720x^2y^2). The expression (12x \cdot 36y) simplifies to (432xy). Therefore, ((10x \cdot 36y) \cdot (2x \cdot y)) is not equal to (12x \cdot 36y).
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12x - 5y equals 30 and y equals 2x - 6 what is the y value?
12x - 5(2x - 6) = 30 12 x - 10x + 30 = 30 2x = 0, x = 0 y = -6
What is the point of intersection between the parabolas of y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?
If: y = 3x^2 +10x +11 and y = 2 -2x -x^2 Then: 3x^2 +10x +11 = 2 -2x -x^2 Transposing terms: 4x^2 +12X +9 = 0 Factorizing the above: (2x+3)(2x+3) = 0 meaning x = -3/2 By substitution into original equations intersection is at (-3/2, 11/4)
What is the point of contact when the parabolas of y equals 2 -2x -x squared and y equals 3x squared plus 10x plus 11 meet each other on the coordinated grid?
If: y = 2 -2x -x^2 and y = 3x^2 +10x +11 Then: 3x^2 +10X +11 = 2 -2x -x^2 Or: 4x^2 +12x +9 = 0 Factorizing the above: (2x+3)(2x+3) = 0 meaning x = -3/2 When x = -3/2 then by substitution y = 11/4 Therefore point of contact is at: (-3/2, 11/4)
What is the ordered pair for the equations 12x-5y30 and y2x-6?
I assume you mean...,12X - 5Y = 30Y = 2X - 6You are given Y, so insert it into the top equation above.12X - 5(2X - 6) = 3012X - 10X + 30 = 302X = 0X = 0=====so, obviously,Y = - 6======Check.12(0) - 5(- 6) = 3030 = 30========checks(0, - 6)=======Ordered pair.
What is the point of contact that the parabolas of y equals 2 -2x -x squared and y equals 3x squared plus 10x plus 11 make with each other showing work?
If: y = 2 -2x -x^2 and y = 3x^2 +10x +11 Then: 3x^2 +10x +11 = 2 -2x -x^2 So it follows that: 4x^2 +12x +9 = 0 Using the quadratic equation formula: x = -3/2 and x also = -3/2 Therefore by substitution the point of contact is at: (-3/2, 11/4)
10x - 3y plus 2x - 4y?
10x+2x-3y-4y=12x-7y
What is 10x-5y plus 2x-3y?
12x-8y
12x - 5y equals 30 and y equals 2x - 6 what is the y value?
12x - 5(2x - 6) = 30 12 x - 10x + 30 = 30 2x = 0, x = 0 y = -6
What is the x value of 12x - 5y equals 30 y equals 2x - 6?
Substitute 2x - 6 for y in first equation: 12x - 5(2x - 6) = 30 ie 12x - 10x + 30 = 30 so 2x = 0 making x = 0 and y = -6
How do you factor 12x squared -3y squared?
15
What is the point of contact of the following parabolas y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?
If: y = 3x^2 +10x +11 and y = 2 -2x -x^2 Then: 3x^2 +10x +11 = 2 -2x -x^2 Transposing terms: 4x^2 +12x +9 = 0 Factorizing: (2x +3)(2x +3) = 0 => x = -3/2 and also x = -3/2 Therefore by substituting the point of contact is at: (-3/2, 11/4)
What is the point of intersection between the parabolas of y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?
If: y = 3x^2 +10x +11 and y = 2 -2x -x^2 Then: 3x^2 +10x +11 = 2 -2x -x^2 Transposing terms: 4x^2 +12X +9 = 0 Factorizing the above: (2x+3)(2x+3) = 0 meaning x = -3/2 By substitution into original equations intersection is at (-3/2, 11/4)
What is the point of contact when the parabolas of y equals 2 -2x -x squared and y equals 3x squared plus 10x plus 11 meet each other on the coordinated grid?
If: y = 2 -2x -x^2 and y = 3x^2 +10x +11 Then: 3x^2 +10X +11 = 2 -2x -x^2 Or: 4x^2 +12x +9 = 0 Factorizing the above: (2x+3)(2x+3) = 0 meaning x = -3/2 When x = -3/2 then by substitution y = 11/4 Therefore point of contact is at: (-3/2, 11/4)
How do you factor 20x2 plus 22xy plus 6y2?
20x2 + 22xy + 6y2 = 20x2 + 10xy + 12xy + 6y2 = 10x(2x + y) + 6y(2x + y) = (2x + y)(10x + 6y) = 2(2x + y)(5x + 3y)
What is the ordered pair for the equations 12x-5y30 and y2x-6?
I assume you mean...,12X - 5Y = 30Y = 2X - 6You are given Y, so insert it into the top equation above.12X - 5(2X - 6) = 3012X - 10X + 30 = 302X = 0X = 0=====so, obviously,Y = - 6======Check.12(0) - 5(- 6) = 3030 = 30========checks(0, - 6)=======Ordered pair.
How do you solve -12x equals 6y?
its just a line, there are many answers that would work -12x-6y=0 -12x=6y x=-y/2 y=-2x
What is the point of contact that the parabolas of y equals 2 -2x -x squared and y equals 3x squared plus 10x plus 11 make with each other showing work?
If: y = 2 -2x -x^2 and y = 3x^2 +10x +11 Then: 3x^2 +10x +11 = 2 -2x -x^2 So it follows that: 4x^2 +12x +9 = 0 Using the quadratic equation formula: x = -3/2 and x also = -3/2 Therefore by substitution the point of contact is at: (-3/2, 11/4)
