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If: y = 3x^2 +10x +11 and y = 2 -2x -x^2

Then: 3x^2 +10x +11 = 2 -2x -x^2

Transposing terms: 4x^2 +12x +9 = 0

Factorizing: (2x +3)(2x +3) = 0 => x = -3/2 and also x = -3/2

Therefore by substituting the point of contact is at: (-3/2, 11/4)

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Q: What is the point of contact of the following parabolas y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?
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