If for x = -1 we find the same value of y in both equations, then x = -1 will be a part of the solution of the system.Let's suppose that x = -1 is the x-coordinate of the solution of the given systemx + y = 4x - y = 6.x + y = 4-1 + y = 4-1 + 1 + y = 4 + 1y = 5x - y = 6-1 - y = 6-1 - 6 + y - y = 6 - 6 + y-7 = ySince we have two different values for y, we say that x = -1 is not a part of the solution for the given system.
solution: y = 0 x = -1
There is one solution for x and one solution for y. The solution is: x = -1 ; y = 2
If you mean y = x+5 and x is -1 then y = 4
If you mean: x+y = 1 then yes (0, 1) is a solution and the other is (1, 0) for the points of a straight line equation
In the equations Y=X-1 and Y=-X+1, the solution is (1,0)
The solution is: x = 1 and y = -1
If for x = -1 we find the same value of y in both equations, then x = -1 will be a part of the solution of the system.Let's suppose that x = -1 is the x-coordinate of the solution of the given systemx + y = 4x - y = 6.x + y = 4-1 + y = 4-1 + 1 + y = 4 + 1y = 5x - y = 6-1 - y = 6-1 - 6 + y - y = 6 - 6 + y-7 = ySince we have two different values for y, we say that x = -1 is not a part of the solution for the given system.
solution: y = 0 x = -1
There is one solution for x and one solution for y. The solution is: x = -1 ; y = 2
x+y=1
0
If you mean y = x+5 and x is -1 then y = 4
If you mean: x+y = 1 then yes (0, 1) is a solution and the other is (1, 0) for the points of a straight line equation
If by that you mean x= 1 and y= 2 then yes (1,2) is a solution
y = x - 1 y - x = 3 y = x - 1 y = x + 3 Since both equations represent straight lines that have equal slopes, 1, then the lines are parallel to each other. That is that the lines do not intersect, and the system of the equations does not have a solution.
Given: x + y = 5 2x + y = 6 We can subtract the second equation from the first to get: -x = -1 x = 1. From there, substituting back in to the first equation yields: 1 + y = 5 y = 4. The solution is (1, 4).