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Is the equation x plus y equals 4 linear or not?
It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
Find the midpoint of the segment below and enter its coordinates as an ordered pair?
This can be done with the equation (x1+x2)/2, (y1+y2)/2 which, when solved, creates a (x,x) solution, or a coordinate pair solution. if you had the points (2,4) and (4,8) you would put x1 (2) plus (+) x2 (4) divided by 2, and 2+4 is 6, and 6/2 is 3, so we know our midpoint x value is 3. Then, we would plug in our 'y' values, so we would have y1 (4) + y2 (8) and 4+8 = 12 and 12/2 is 6, so our solution coordinate ordered pair would be (3,6).
X1 plus y2?
4
How to get the equation of a line that passes through these two points?
(y-y1)=(y2-y1/x2-x1)(x-x1)
How do you do equations and graphs for slope?
The equation for the slope between the points A = (x1, y1) and B = (x2, y2) = (y2 - y1)/(x2 - x1), provided x1 is different from x2. If x1 and x2 are the same then the slope is not defined.
What is the formula for calculating the change in the independent variable, delta x, in a mathematical function or equation?
The formula for calculating the change in the independent variable, delta x, in a mathematical function or equation is: delta x x2 - x1 Where x2 is the final value of the independent variable and x1 is the initial value of the independent variable.
The difference between undefined slope and zero slope is?
The slope of a line between Points 1 and 2 is defined as m = (Y2 - Y1) / (X2 - X1) where coordinates for Point 1 is (X1,Y1) and Point 2 is (X2,Y2). So if the value of Y2-Y1 = 0 then the Slope is zero. If the value of X2 - X1 = zero then the equation is undetermined because you can't solve an equation with a 0 value in the denominator. or m = (Y2 - Y1) / 0
Determine if the point 3-4 is a solution for the equation y equals 8 -4x?
use the formula y-y1=m(x-x1)
X plus one over x squared plus two?
it equals x1 it equals x1
Find number of integer solution of X1 x2 x324?
find number of integer solution of X1+x2+x3=24
What is the proof of newton raphson iterative equation?
Suppose you have a differentiable function of x, f(x) and you are seeking the root of f(x): that is, a solution to f(x) = 0.Suppose x1 is the first approximation to the root, and suppose the exact root is at x = x1+h : that is f(x1+h) = 0.Let f'(x) be the derivative of f(x) at x, then, by definition,f'(x1) = limit, as h tends to 0, of {f(x1+h) - f(x1)}/hthen, since f(x1+h) = 0, f'(x1) = -f(x1)/h [approx] or h = -f'(x1)/f(x1) [approx]and so a better estimate of the root is x2 = x1 + h = x1 - f'(x1)/f(x1).
Is the equation x plus y equals 4 linear or not?
It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
Give an example of an equation that is an identity?
An identity is an equation that is always true, for any value of the variable or variables. Here are some examples: x + x = 2x a + b = b + a x1 = x
How do you find the The initial range of Bisection method?
If this is in the context of finding a root of an equation, the answer is to make some guesses. Find value x1 and x2 such that f(x1) and f(x2) have opposite signs. Then, provided that f is a continuous function over (x1, x2), the bisection method will find its root.
Find the midpoint of the segment below and enter its coordinates as an ordered pair?
This can be done with the equation (x1+x2)/2, (y1+y2)/2 which, when solved, creates a (x,x) solution, or a coordinate pair solution. if you had the points (2,4) and (4,8) you would put x1 (2) plus (+) x2 (4) divided by 2, and 2+4 is 6, and 6/2 is 3, so we know our midpoint x value is 3. Then, we would plug in our 'y' values, so we would have y1 (4) + y2 (8) and 4+8 = 12 and 12/2 is 6, so our solution coordinate ordered pair would be (3,6).
X1 plus y2?
4
How to get the equation of a line that passes through these two points?
(y-y1)=(y2-y1/x2-x1)(x-x1)
