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Is (1 -1) a solution to x y?
If you mean: x+y = 1 then yes (0, 1) is a solution and the other is (1, 0) for the points of a straight line equation
How can x plus 1 equals 2y if y-1 equals x?
solution: y = 0 x = -1
How many solutions to y equals x-1 and y equals -x plus 1?
y = x - 1 y = -x + 1 (add both the equations) 2y = 0 y = 0 when y = 0, x = 1 So that the only solution is the intersection point of the lines, (1, 0).
What are the solutions for x when y equals 0 in the quadratic function y equals x2 plus x?
y = x2 + x = 0 x (X + 1) = 0 x = 0 is one solution x = -1 is the other
Is 0 0 a solution to x equals y?
Yes.
Is (1 -1) a solution to x y?
If you mean: x+y = 1 then yes (0, 1) is a solution and the other is (1, 0) for the points of a straight line equation
How can x plus 1 equals 2y if y-1 equals x?
solution: y = 0 x = -1
How many solutions to y equals x-1 and y equals -x plus 1?
y = x - 1 y = -x + 1 (add both the equations) 2y = 0 y = 0 when y = 0, x = 1 So that the only solution is the intersection point of the lines, (1, 0).
What are the solutions for x when y equals 0 in the quadratic function y equals x2 plus x?
y = x2 + x = 0 x (X + 1) = 0 x = 0 is one solution x = -1 is the other
Is -1 -1 a solution to x y?
0
What is the solution to the equations. 2x - y -3 x y 0?
Without any equality signs the given terms can't be considered to be equations. But if you mean: 2x-y = -3 and x+y = 0 then x = -1 and y = 1
Is there a no solution in y equals x-1 and y equals -x plus 1?
In the equations Y=X-1 and Y=-X+1, the solution is (1,0)
Which ordered pair is a solution to the equation y - 2x 6?
For example, if you have (0, 6) or (3, 1). Which of them is a solution to y - 2x = 6? Check (0, 6): y - 2x = 6, substitute 0 for x, and 6 for y into the equation 6 - 2(0) =? 6 6 - 0 =? 6 6 = 6 True, then (0, 6) is a solution. Check (3, 1): y - 2x = 6, substitute 3 for x, and 1 for y into the equation 1 - 2(3) =? 6 1 - 6 =? 6 -5 = 6 False, then (3, 1) is not a solution.
Why does't the number get bigger with multiplication?
The assertion in the question is false. The result of a multiplication depends on the values. Given two numbers X and Y, if X < 0 and if Y < 0 then X*Y is greater than either; if X > 1 and if Y > 1 then X*Y is greater than either; if X < 0 and if Y > 1 then X*Y is smaller than either; if X > 1 and if Y < 0 then X*Y is smaller than either; if 0 < X < 1 and if 0 < Y < 1 then X*Y is smaller than either; If X < 0 and if 0 < Y < 1 then X*Y is greater than X but smaller than Y; If 0 < X < 1 and if Y > 1 then X*Y is greater than X but smaller than Y; If 0 < X < 1 and if Y < 0 then X*Y is smaller than X but greater than Y; If X > 1 and if 0 < Y < 1 then X*Y is smaller than X but greater than Y.
How dual of xor is equal to its complement?
| x | y | x' | y' | x⊕y | x'⊕y' | ---------------------------------- | 0 | 0 | 1 | 1 | 0 | 0 | | 0 | 1 | 1 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 0 | 0 |
What is the solution for y equals 1 y equals -4x and y equals -12x?
1). y = 12). y = -4x3). y = -12xA "solution" is a pair of numbers ... one for 'x' and one for 'y' ... that makes the statements true.There is no solution for the group of all three equations.The solution for #1 and #2 taken together is (-1/4 , 1).The solution for #1 and #3 taken together is (-1/12 , 1).The solution for #2 and #3 taken together is (0, 0).
How dual of XOR gate is equal to its complement?
| x | y | x' | y' | x⊕y | x'⊕y' | ---------------------------------- | 0 | 0 | 1 | 1 | 0 | 0 | | 0 | 1 | 1 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 0 | 0 |
