It is: (c-4)(c-8) when factored
(n - 4)(n - 12)
x 2 - 5x - 36 = 0; factor. (x-9)(x+4) = 0; set each factor = 0. x - 9 = 0 and x + 4 = 0 So, x = 9 and x = -4.
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
(x - 5)(x + 4)
(x + 2)(x - 4)
4(x - 1)(x + 1)
The factors are -1(2x + 1)(3x + 4)
(x-1)(x-4)
It is the difference of squares. (x-4) and (x+4) <--- answer
x(x + 3)(x - 4)
x^2 - y^2 - 4 is in its simplest form.
2x squared minus 4
4(y - 3)(y + 3)
(3r - 2)(3r - 2) or (3r - 2) squared.
It is: (3x+4)(2x-3) when factored
(2x - 4)(2x + 3) The key is to look for all the factor pairs of 12.