(5y - 2)(5y + 2)
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It is: (c-4)(c-8) when factored
(n - 4)(n - 12)
x 2 - 5x - 36 = 0; factor. (x-9)(x+4) = 0; set each factor = 0. x - 9 = 0 and x + 4 = 0 So, x = 9 and x = -4.
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
(x - 5)(x + 4)