no. its an exponential with a vertical zero axis
No because when you place x in terms of y, you get y = 1/x ( by dividing both the sides by x). This is not linear because the power of x is (-1) and for a linear relationship, you need the power of x to be (1).
Multiply through by xy to bring terms in x and y to the top, and you find an xy term popping up as well. So it's non--linear. On the other hand if you plot (1/y) vs (1/x) it is linear in terms of those particular variables
So far you know that: x=-8 xy=1 so xy means x times y. If you split xy. y=1/x or y=1/-8 1/-8= -0.125 You can find out that this is correct with the formula xy=1 because -0.125 x -8 is 1.
-1/8 -8*-1/8 = 1
no. its an exponential with a vertical zero axis
No because when you place x in terms of y, you get y = 1/x ( by dividing both the sides by x). This is not linear because the power of x is (-1) and for a linear relationship, you need the power of x to be (1).
That is the commutative property of equality.
xy = x ÷x y = 1
Multiply through by xy to bring terms in x and y to the top, and you find an xy term popping up as well. So it's non--linear. On the other hand if you plot (1/y) vs (1/x) it is linear in terms of those particular variables
Yes. You can tell by the fact that both variables are raised to the first power.
So far you know that: x=-8 xy=1 so xy means x times y. If you split xy. y=1/x or y=1/-8 1/-8= -0.125 You can find out that this is correct with the formula xy=1 because -0.125 x -8 is 1.
-1/8 -8*-1/8 = 1
It equals y+1
If Y = 0 then there is no value of X such that XY = 1.
x+xy=8 xy=-x+8 y=-1+8/x
"xy" refers to the product of "x" and "y". Just substitute the variables for numbers, and do the multiplication.