If you have -2x = 0, to solve for x, divide each side by two. That results in x = -0/2, or x = 0. So there is only one solution.
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The solution set is the set of all points representing solutions.
No. They can just as well have zero solutions, several solutions, or even infinitely many solutions.
It depends on the polynomial and your degree of sophistication. In the complex domain, it will have six solutions, although not all of them need be different. If the coefficients are all real, then it will have 0, 2, 4 or 6 real solutions in the real domain.
You may be able to give a formula that represents all the solutions. For example, the equation sin(x) = 0 where x is real, has infinitely many solutions but they can be summarised, very simply, as x = n*pi radians (180*n degrees) where n is any integer. Some solution sets are harder to summarise.You may be able to give a formula that represents all the solutions. For example, the equation sin(x) = 0 where x is real, has infinitely many solutions but they can be summarised, very simply, as x = n*pi radians (180*n degrees) where n is any integer. Some solution sets are harder to summarise.You may be able to give a formula that represents all the solutions. For example, the equation sin(x) = 0 where x is real, has infinitely many solutions but they can be summarised, very simply, as x = n*pi radians (180*n degrees) where n is any integer. Some solution sets are harder to summarise.You may be able to give a formula that represents all the solutions. For example, the equation sin(x) = 0 where x is real, has infinitely many solutions but they can be summarised, very simply, as x = n*pi radians (180*n degrees) where n is any integer. Some solution sets are harder to summarise.
No. Some have two solutions where as some have none.