To convert the equation 8x - 5y = -40 into slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, you need to solve for y. First, isolate y by subtracting 8x from both sides to get -5y = -8x - 40. Then, divide by -5 to get y = 8/5x + 8, which is the slope-intercept form of the equation. The slope is 8/5 and the y-intercept is 8.
8-8x=8x+18 Through simple algebra, this can be manipulated to solve for x: 8=16x+18 -10=16x -5/8=x
8x+40
8x+7=55 8x=55-7 8x=48 x=48/8 x=6
Let me assume that this equation is -2 -8x = 40 It's usually best to move all the purely numerical items to one side first. Let me move the -2. Then, to do this I add 2 to both sides. -2 - 8x +2 = -8x = 40 + 2 = 42 or -8x = 42 Now, to yield x 'by itself' let me divide both sides by -8. (-8x)/-8 = x = 42/(-8) = -21/4 or x = -21/4
8x + 8=40 8x=40-8 8x=32 x=32/8 x=4
x*8 is equal to 8x.
To convert the equation 8x - 5y = -40 into slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, you need to solve for y. First, isolate y by subtracting 8x from both sides to get -5y = -8x - 40. Then, divide by -5 to get y = 8/5x + 8, which is the slope-intercept form of the equation. The slope is 8/5 and the y-intercept is 8.
8-8x=8x+18 Through simple algebra, this can be manipulated to solve for x: 8=16x+18 -10=16x -5/8=x
8x+40
If x = 2 then 40-(8*2) = 24
8(30) - 40 = 240 - 40 = 200.
x2 = 8xx2- 8x = 0x(x - 8) = 0x = 0 ;x - 8 = 0x = 8
(13-2y)/8
8x+7=55 8x=55-7 8x=48 x=48/8 x=6
Let me assume that this equation is -2 -8x = 40 It's usually best to move all the purely numerical items to one side first. Let me move the -2. Then, to do this I add 2 to both sides. -2 - 8x +2 = -8x = 40 + 2 = 42 or -8x = 42 Now, to yield x 'by itself' let me divide both sides by -8. (-8x)/-8 = x = 42/(-8) = -21/4 or x = -21/4
8(x+5) is equivalent to 8x+40