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What is the complex conjugate of a plus bi?
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)
What are factors of 576 that add up to -12?
564
How do you get the solution to 6 divided by the square root of -10?
16
How do you simplify i plus 6i?
answer is 7i, since its the same thing as: i + (i + i + i + i + i + i)
What is 4 plus 6i times -7 plus you simplified in standard form?
(4 + 6i)*(-7) = -28 - 42iAnd just because i = sqrt(-1), I am not something that you can multiply or simplify.
What is the complex conjugate complex number-8-6i?
-6i-8
What is the complex conjugate complex number 8 6i?
Oh, dude, the complex conjugate of 8 + 6i is just flipping the sign of the imaginary part, so it's 8 - 6i. It's like changing your mood from happy to grumpy, but in the world of math. So yeah, that's the deal with complex conjugates.
What is the complex conjugate of 2-6i?
2+6i
How do you rationalize complex numbers?
you must multiply by the conjagate. which is the denominator with the middle sign changed....(5+6i)...conjagate= (5-6i)....
Examples of complex numbers?
5+6i , -2-2i , 100+i.A complex number consists of a real part and an imaginary part: a+bi where 'i' is the imaginary unit (sq.rt(-1)).
What is the complex conjugate of a plus bi?
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)
What is the complex form of 4 plus 4i plus 4 plus 6i?
the problem: what is 4 + 4i + 4 + 6i what you do is add the real and imaginary parts, thus: 4+4 and 4i+6i = 8+10i answer.
What is The square root of 25-2times the square root of -36 plus the square root of four - the square root of 121?
Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
What are factors of 576 that add up to -12?
564
How do you find a 4th degree polynomial with zeros x equals 4 x equals -3 and x equals 6i?
There are only three roots given so, in general, there is no unique answer. However, if it is a real polynomial, then its complex roots must come in conjugate pairs. Then 6i is a root implies that -6i is a root. So the polynomial is (x - 4)(x + 3)(x + 6i)(x - 6i) = (x2 - x - 12)(x2 + 36) = x4 + 36x2 - x3 - 36x - 12x2 - 432 = x4 - x3 + 24x2 - 36x - 432
In algebra what is the square root of -36?
6i which also means 6 as an imaginary number.
How can you uninstall developer 6i from your computer?
how can i unistall developer 6i from my winows7
