Oh, dude, the complex conjugate of 8 + 6i is just flipping the sign of the imaginary part, so it's 8 - 6i. It's like changing your mood from happy to grumpy, but in the world of math. So yeah, that's the deal with complex conjugates.
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The complex conjugate of a complex number is obtained by changing the sign of the imaginary part. In this case, the complex number is 8 + 6i. Therefore, the complex conjugate of 8 + 6i is 8 - 6i. The complex conjugate helps in simplifying complex number operations and is crucial in various mathematical applications.
Since you didn't show an operator, we'll use:
1. 8-6i
2. 8+6i
3. 8 times 6i = 48i
The complex conjugates are:
1. 8+6i
2. 8-6i
3. -48i
-6i-8
A "complex number" is a number of the form a+bi, where a and b are both real numbers and i is the principal square root of -1. Since b can be equal to 0, you see that the real numbers are a subset of the complex numbers. Similarly, since a can be zero, the imaginary numbers are a subset of the complex numbers. So let's take two complex numbers: a+bi and c+di (where a, b, c, and d are real). We add them together and we get: (a+c) + (b+d)i The sum of two real numbers is always real, so a+c is a real number and b+d is a real number, so the sum of two complex numbers is a complex number. What you may really be wondering is whether the sum of two non-real complex numbers can ever be a real number. The answer is yes: (3+2i) + (5-2i) = 8. In fact, the complex numbers form an algebraic field. The sum, difference, product, and quotient of any two complex numbers (except division by 0) is a complex number (keeping in mind the special case that both real and imaginary numbers are a subset of the complex numbers).
2.2 x 10-8
Nearly any number you can think of is a Real Number. So 8 is a real number.
If the last three digits of a number are divisible by 8, the whole number is divisible by 8.