No
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Yes, 0 is a factor of 8 because any number multiplied by 0 is equal to 0. In this case, 0 multiplied by 8 is equal to 0.
8. 300 ends in 0 or 5, so 5 is a factor 300 is divisible by 4 and 5, so 20 is a factor 300 is even and 3 + 0 + 0 = 3, so 6 is a factor Leaving 8 to be the non factor Testing if 8 is a factor: 4 x 3 + 2 x 0 + 0 = 12; 4 x 0 + 2 x 1 + 2 = 4 which is not 8, so 300 is not divisible by 8.
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}
x2-9x+8=0 has two solutions:x = 8x = 1
It is when factored: (N-8)(N+3)
8 is not an integer factor of 42.