Q: N²-5n-24 0 Middle Term Factor

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To factor 4w^2 + 12w + 4 = 0, first divide the equation by 4 to simplify it: w^2 + 3w + 1 = 0. Then, decompose the middle term (3w) into two terms whose product is the product of the coefficient of w^2 and the constant term (1): (w+1)(w+1) = 0. Therefore, the factors are (w+1)(w+1) = 0.

x^(2)- x + 2 (x -2)( x + 1) NB This does NOT factor becasue '-2' X (+)1 = -2 ( as the middle term. Since the middle term is '-1x' , then '-1' Not equal to '-2'. However, x^(2) - x -2 does factor to ( x - 2)(x + 1)

This is called an incomplete quadratic equation because there is no linear term. aX2 +( bX)+ c = 0 The middle term is not there, but this is quite solvable.

n^2 + 5n = 0Where there is no constant term, then there is one monomial and one binomial factors. In this case the monomial is n and the binomial is (n + 5) So n*(n + 5) = 0 which leads to the solutions n = 0 or n = 5.

No because 0 doesn't do anything. also, 0 doesn't have any other factor other than 0

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To factor 4w^2 + 12w + 4 = 0, first divide the equation by 4 to simplify it: w^2 + 3w + 1 = 0. Then, decompose the middle term (3w) into two terms whose product is the product of the coefficient of w^2 and the constant term (1): (w+1)(w+1) = 0. Therefore, the factors are (w+1)(w+1) = 0.

x^(2)- x + 2 (x -2)( x + 1) NB This does NOT factor becasue '-2' X (+)1 = -2 ( as the middle term. Since the middle term is '-1x' , then '-1' Not equal to '-2'. However, x^(2) - x -2 does factor to ( x - 2)(x + 1)

This is called an incomplete quadratic equation because there is no linear term. aX2 +( bX)+ c = 0 The middle term is not there, but this is quite solvable.

The answer depends on the sign of the growth factor which is less than 1. There is no factor that is "less then 1"!If the first term is 0, the growth factor has no effect.A positive growth factor less than 1 results in a sequence that decreases towards 0. A growth factor greater than 1 results in a sequence that increases without limit if the initial value is positive, or decreases without limit (towards minus infinity) if the first term is negative.

n^2 + 5n = 0Where there is no constant term, then there is one monomial and one binomial factors. In this case the monomial is n and the binomial is (n + 5) So n*(n + 5) = 0 which leads to the solutions n = 0 or n = 5.

No because 0 doesn't do anything. also, 0 doesn't have any other factor other than 0

Yes, 0 is a factor of 8 because any number multiplied by 0 is equal to 0. In this case, 0 multiplied by 8 is equal to 0.

No, for 0 to be a factor, the numbers would have to be divisible by 0. You can't divide any number by 0, so it can't be a factor.1 is a factor of every positive number.

If a number has 5 as a factor, it will end in 0 or 5.

5 is a factor of integers that end in 5 or 0, such as 15, 40, or 135. It is not a factor of integers that do not end in 5 or 0.

x-a is a factor of the polynomial p(x),if p(a)=0.also,if x-a is a factor of p(x), p(a)=0.

The greatest common factor of 0 and any other number is the other number. So the greatest common factor of 0 and 100,000 is 100,000.