It is when factored: (N-8)(N+3)
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To factor 4w^2 + 12w + 4 = 0, first divide the equation by 4 to simplify it: w^2 + 3w + 1 = 0. Then, decompose the middle term (3w) into two terms whose product is the product of the coefficient of w^2 and the constant term (1): (w+1)(w+1) = 0. Therefore, the factors are (w+1)(w+1) = 0.
x^(2)- x + 2 (x -2)( x + 1) NB This does NOT factor becasue '-2' X (+)1 = -2 ( as the middle term. Since the middle term is '-1x' , then '-1' Not equal to '-2'. However, x^(2) - x -2 does factor to ( x - 2)(x + 1)
This is called an incomplete quadratic equation because there is no linear term. aX2 +( bX)+ c = 0 The middle term is not there, but this is quite solvable.
No because 0 doesn't do anything. also, 0 doesn't have any other factor other than 0
n^2 + 5n = 0Where there is no constant term, then there is one monomial and one binomial factors. In this case the monomial is n and the binomial is (n + 5) So n*(n + 5) = 0 which leads to the solutions n = 0 or n = 5.