I think you mean r2 -7r -8 = 0. If so, then factor it: (r+1)(r-8) = 0
Then set r+1 = 0, r+1-1=-1, r = -1 Set r-8 =0, r-8+8 = 8 so r = 8
n = 3/2, n = 2
a = 0. That is because a = 0 implies that there is no quadratic term and so the equation is not a quadratic!There may be some who make claims depending on the value of the discriminant (which is b2-4ac). That is true only for elementary mathematics. In more advanced mathematics (complex analysis), the quadratic equation can be used in all cases except when a = 0: the value of the discriminant is irrelevant.a = 0. That is because a = 0 implies that there is no quadratic term and so the equation is not a quadratic!There may be some who make claims depending on the value of the discriminant (which is b2-4ac). That is true only for elementary mathematics. In more advanced mathematics (complex analysis), the quadratic equation can be used in all cases except when a = 0: the value of the discriminant is irrelevant.a = 0. That is because a = 0 implies that there is no quadratic term and so the equation is not a quadratic!There may be some who make claims depending on the value of the discriminant (which is b2-4ac). That is true only for elementary mathematics. In more advanced mathematics (complex analysis), the quadratic equation can be used in all cases except when a = 0: the value of the discriminant is irrelevant.a = 0. That is because a = 0 implies that there is no quadratic term and so the equation is not a quadratic!There may be some who make claims depending on the value of the discriminant (which is b2-4ac). That is true only for elementary mathematics. In more advanced mathematics (complex analysis), the quadratic equation can be used in all cases except when a = 0: the value of the discriminant is irrelevant.
I would clean that up a little bit to make it look like, y^2+4y-4. which will factor out into, (y+2)*(y-2) So the two possible answers is -2 and 2
The answer is 3. :p
Given a value for the variable x, you find (calculate) the corresponding value of y. These (x, y) pairs are part of the table. You cannot complete the table because there are infinitely many possible values of x.
-0.82 , -4.82
Using the discriminant formula for a quadratic equation k has a value of 8/25 or maybe 0.
n = 3/2, n = 2
you could get irrational values for x, rational values for x, imaginary values for x, and perfect squares for x. although perfect squares are rational answers so i guess i can think of three possible answer types. :) oh you can get zero for the value of x. there you go.
D
dunctions are not set equal to a value
a = 0. That is because a = 0 implies that there is no quadratic term and so the equation is not a quadratic!There may be some who make claims depending on the value of the discriminant (which is b2-4ac). That is true only for elementary mathematics. In more advanced mathematics (complex analysis), the quadratic equation can be used in all cases except when a = 0: the value of the discriminant is irrelevant.a = 0. That is because a = 0 implies that there is no quadratic term and so the equation is not a quadratic!There may be some who make claims depending on the value of the discriminant (which is b2-4ac). That is true only for elementary mathematics. In more advanced mathematics (complex analysis), the quadratic equation can be used in all cases except when a = 0: the value of the discriminant is irrelevant.a = 0. That is because a = 0 implies that there is no quadratic term and so the equation is not a quadratic!There may be some who make claims depending on the value of the discriminant (which is b2-4ac). That is true only for elementary mathematics. In more advanced mathematics (complex analysis), the quadratic equation can be used in all cases except when a = 0: the value of the discriminant is irrelevant.a = 0. That is because a = 0 implies that there is no quadratic term and so the equation is not a quadratic!There may be some who make claims depending on the value of the discriminant (which is b2-4ac). That is true only for elementary mathematics. In more advanced mathematics (complex analysis), the quadratic equation can be used in all cases except when a = 0: the value of the discriminant is irrelevant.
The quadratic equation is y=ax^2 +bx +c. So, you substitute in the values of a, b, and c to the quadratic formula (x= -b +/- \|b^2-4ac all over 2a) in order to find the x value then, substitute in x to the quadratic equation and solve. You will have point (x,y) to graph
If x is the unknown or variable in an equation it can have many possible maximum or minimum values
It is the value of the discriminant of a quadratic equation.
You substitute the value of the variable into the quadratic equation and evaluate the expression.
from the equation using the formula -b/2a to find x value. from there substitute values of x before and after in equation.for example if x is 2 use other x values as 1 and 3.