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Is 702 divisible by 6?
Yes. 702 is even and so divisible by 2 7 + 0 + 2 = 9 which is divisible by 3 702 is divisible by 2 & 3 and so is divisible by 6.
How do you know 120 is divisible by 3 and 5?
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
What is divisible by 417?
If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.
Is 1 2 0 3 8 divisible by 4 and 9?
1, 2, 0, 3 and 8 are not divisible by 4 and/or 9. Neither is 12038.
Is 2390 divisible by 3 and 5?
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
Is 4320 divisible by 2 3 5 9 or 10?
Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10
Is 230 divisible by 2 3 and 5?
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
Can 534 divisble by 2 3 5 9 10?
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
Is 702 divisible by 6?
Yes. 702 is even and so divisible by 2 7 + 0 + 2 = 9 which is divisible by 3 702 is divisible by 2 & 3 and so is divisible by 6.
How do you know 120 is divisible by 3 and 5?
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
Is 1 2 0 3 8 divisible by 4 and 9?
1, 2, 0, 3 and 8 are not divisible by 4 and/or 9. Neither is 12038.
Is 2390 divisible by 3 and 5?
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
Is 3058 divisible by 6?
No. To be divisible by 6, a number must be even (divisible by 2) and divisible by 3. Although 3058 is even, it is not divisible by 3 since 3+0+5+8 = 16 which is not divisible by 3. Thus is it not divisible by 6.
Is 423 divisible by 6?
A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
How do you know if 54132 is divisible by 6?
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.
Is 7002 divisible by 3?
No... because 10 is not a factor of 3. 7+0+0+2= 10
Is the number 432 divisible by 2 3 5 6 9 10?
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.
