yes, 0 is divisible by everything.
To determine if 320230320132 is divisible by 6, it must be divisible by both 2 and 3. The number is even (it ends in 2), so it's divisible by 2. For divisibility by 3, the sum of its digits (3 + 2 + 0 + 2 + 3 + 0 + 3 + 2 + 0 + 1 + 3 + 2 = 21) is divisible by 3. Therefore, 320230320132 is divisible by 6.
Yes. 702 is even and so divisible by 2 7 + 0 + 2 = 9 which is divisible by 3 702 is divisible by 2 & 3 and so is divisible by 6.
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.
1, 2, 0, 3 and 8 are not divisible by 4 and/or 9. Neither is 12038.
To determine if 320230320132 is divisible by 6, it must be divisible by both 2 and 3. The number is even (it ends in 2), so it's divisible by 2. For divisibility by 3, the sum of its digits (3 + 2 + 0 + 2 + 3 + 0 + 3 + 2 + 0 + 1 + 3 + 2 = 21) is divisible by 3. Therefore, 320230320132 is divisible by 6.
Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
Yes. 702 is even and so divisible by 2 7 + 0 + 2 = 9 which is divisible by 3 702 is divisible by 2 & 3 and so is divisible by 6.
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.
1, 2, 0, 3 and 8 are not divisible by 4 and/or 9. Neither is 12038.
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
not divisible by 9.but it is divisible by 4.
To determine if 1011 is divisible by each of these numbers: It is not divisible by 2, as it is odd. It is not divisible by 5 or 10, as it does not end in 0 or 5. For 3, the sum of the digits (1+0+1+1=3) is divisible by 3, so 1011 is divisible by 3. For 9, the sum of the digits is also divisible by 9, so it is not divisible by 9. In summary, 1011 is only divisible by 3.
Yes, 1044 is divisible by 2, 3, 6, and 9. It is even, so it is divisible by 2. The sum of its digits (1 + 0 + 4 + 4 = 9) is divisible by 3, making it divisible by 3 and 9 as well. However, 1044 is not divisible by 5 or 10 because it does not end in 0 or 5.