It not divisible by 5 because it does not end 5 or 0 . . . . . . . . . . It is not divisable by 6 because it is not even . . . . . . . . . It is divisible by 3 because all the digits add up to a multiple of 3 (1+5+9= 15) . . . . . . . . So really 159 is only divisible by 3
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159 171 and any thing else which digits add up to something divisible by 3 for example 159 break it down into 1+5+9= 15, 15 is divisible by three so that means 159 is divisble. An example for something not divisible by 3 would be 467 because 4+6+7= 17, and 17 is not divisible by 3, and also anyway there's no way I could list them all because the list would be infinite, because numbers are infinite and go on forever.
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.