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Find two consecutive negative odd integers whose product is 399?
Let the two consecutive negative odd integers be ( x ) and ( x + 2 ). The equation for their product is ( x(x + 2) = 399 ). This simplifies to ( x^2 + 2x - 399 = 0 ). Solving this quadratic equation, we find that the integers are ( -19 ) and ( -17 ), since ( -19 \times -17 = 399 ).
What are consecutive numbers for the number 62?
14, 15, 16 and 17.
What are the 3 consecutive numbers of 48?
The numbers are 15, 16 and 17.
The sum of 3 consecutive integers is 48 what are they?
15, 16 and 17
What 2 consecutive integers have sum -15?
17
3 consecutive integers for -48?
-17, -16 and -15
What is 5985 divided by 15?
399
What are to consecutive odd numbers is 399?
If you are wanting to add odd numbers to get 399, it won't work. If you are wanting to multiply to get 399, it is 19 x 21.
What are the 3 consecutive numbers of 48?
The numbers are 15, 16 and 17.
What are consecutive numbers for the number 62?
14, 15, 16 and 17.
The sum of 3 consecutive integers is 48 what are they?
15, 16 and 17
What 2 consecutive integers have sum -15?
17
What are the two consecutive odd integers have a sum of 32?
15 and 17
What are the five consecutive numbers of 77?
No five consecutive numbers make 77. 13 + 14 + 15 + 16 + 17 = 75 and 14 + 15 + 16 + 17 + 18 = 80 You cannot consider fractional numbers because the concept of consecutive does not apply to fractions.
What are two consecutive odd integers if the sum of them is 32?
The integers are 15 and 17.
The product of what two consecutive odd integers is 255?
15 x 17
Which 2 consecutive numbers add up to 15?
17
