Q: The sum of 3 consecutive integers is 48 what are they?

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The numbers are 46, 48 and 50.

3 consecutive even integers whose sum is 396 are 130, 132 and 134.

-48,-49,-50. i got this by dividing -147 by 3 which is -49 and just adding one and subtracting one from it (-48 and -50).

24 + 25 + 26 = 75

48 1/3, 48 2/3, 48 3/3

Related questions

The numbers are 46, 48 and 50.

It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.

Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.

201

They are are 62, 63 and 64.

3 consecutive even integers whose sum is 396 are 130, 132 and 134.

Let's see if this is true. Assume that their sum is 48. So, x + (x +1) + (x + 2) = 48 3x + 3 = 48 Subtract 3 at both sides; 3x = 45 Divide 3 to both sides; x = 15 x + 1 = 15 + 1 = 16 x + 2 = 15 + 2 = 17 So, 15 + 16 + 17 = 48 Answer: The sum of three consecutive integers such as 15, 16, and 17 is 48.

-48,-49,-50. i got this by dividing -147 by 3 which is -49 and just adding one and subtracting one from it (-48 and -50).

The sum of even integers cannot end with 9. why not

The integers are 16, 17 and 18.

-3,-4,-5

The integers are 24, 25 and 26.