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The two consecutive integers that have a sum of -105 are -53 and -52.
Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.
Two consecutive even integers will be one more and one less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is 25, so the two consecutive integers are 24 and 26.
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
Let's represent the two consecutive integers as x and x + 1. The sum of these two integers is x + (x + 1) = 2x + 1. We are given that this sum equals -30.03, so 2x + 1 = -30.03. Solving for x, we get x = (-30.03 - 1) / 2 = -31.03 / 2 = -15.515. Therefore, the two consecutive integers are -15 and -14.